mysql根据成绩排名次

• （1，2，2，4 , 5）

select t.score,(select count(s.score)+1 from score s where s.score>t.score) rank from score t order by t.score desc;

• （1，2，2，3 , 3）

select t.score,(select count(s.score)+1 from (select s.score,count(s.score) from score s group by score order by score desc) s where s.score>t.score) rank from score t order by t.score desc;