emoji表情检测

 /**
     * 检测是否有emoji表情
     *
     * @param source
     * @return
     */
    public static boolean containsEmoji(String source) {        int len = source.length();        for (int i = 0; i < len; i++) {            char codePoint = source.charAt(i);            if (!isEmojiCharacter(codePoint)) { //如果不能匹配,则该字符是Emoji表情
                return true;
            }
        }        return false;
    }    /**
     * 判断是否是Emoji
     *
     * @param codePoint 比较的单个字符
     * @return
     */
    private static boolean isEmojiCharacter(char codePoint) {        return (codePoint == 0x0) || (codePoint == 0x9) || (codePoint == 0xA) ||
                (codePoint == 0xD) || ((codePoint >= 0x20) && (codePoint <= 0xD7FF)) ||
                ((codePoint >= 0xE000) && (codePoint <= 0xFFFD)) || ((codePoint >= 0x10000)
                && (codePoint <= 0x10FFFF));
    }

 

转载于:https://www.cnblogs.com/84126858jmz/p/5360926.html