日:
SELECT COUNT(1)
FROM STUDENT_BILL WHERE 1=1
AND SUB_MERCHANT_ID = #{merchantId}
AND to_char(PAY_TIME,'yyyy-mm-dd')= to_char(to_date(#{date}, 'yyyy-mm-dd hh24:mi:ss')-#{type},'yyyy-mm-dd') AND STATUS = '1'
AND to_char(PAY_TIME,'yyyy-mm-dd')= to_char(to_date(#{date}, 'yyyy-mm-dd hh24:mi:ss'),'yyyy-mm-dd') AND STATUS = '1'
周:
SELECT COUNT(1)
FROM STUDENT_BILL WHERE 1=1
AND SUB_MERCHANT_ID = #{merchantId}
AND PAY_TIME between trunc(next_day(to_date(#{date}, 'yyyy-mm-dd hh24:mi:ss') - 1, 1)-6) AND trunc(next_day(to_date(#{date}, 'yyyy-mm-dd hh24:mi:ss') - 1, 1)+1) AND STATUS = '1'
AND PAY_TIME between trunc(next_day(to_date(#{date}, 'yyyy-mm-dd hh24:mi:ss') -(1+#{type}*7), 1)-6) AND trunc(next_day(to_date(#{date}, 'yyyy-mm-dd hh24:mi:ss') - (1+#{type}*7), 1)+1) AND STATUS = '1'
月:
SELECT COUNT(1)
FROM STUDENT_BILL WHERE 1=1
AND SUB_MERCHANT_ID = #{merchantId}
AND to_char(PAY_TIME,'yyyy-mm')= to_char(add_months(to_date(#{date}, 'yyyy-mm-dd hh24:mi:ss'),0),'yyyy-mm') AND STATUS = '1'
AND to_char(PAY_TIME,'yyyy-mm')= to_char(add_months(to_date(#{date}, 'yyyy-mm-dd hh24:mi:ss'),-#{type}),'yyyy-mm') AND STATUS = '1'
备注:type的值 :0表示当日,1表示昨天,依次往前,想获取几天一次增加type的值
周和月一样,0表示当月当周,1表示上一月上一周等
周的时间是:周一到周日的交易区间
日期具体获取方式:
//周
select next_day(to_date('2018-8-3','yyyy-MM-dd'),1) from dual;//找到下一周的第一天,也就是日历中的下一周星期日
select next_day(to_date('2018-8-3','yyyy-MM-dd')-8,1) from dual;//找到本周的周日,本周的第一天
select trunc(next_day(to_date('2018-8-3','yyyy-MM-dd')-1,1)-6) from dual;//找到本周的星期一,本周的第二天
select trunc(next_day(to_date('2018-8-3','yyyy-MM-dd')-1,1)+1) from dual;//找到下一周的星期一,下周的第二天
select trunc(next_day(to_date('2018-8-3','yyyy-MM-dd')-8,1)-6) from dual;//找到上周的星期一,上周的第二天
//所以区间为本周一的00:00:00到下周一的00:00:00,而不是到下周天的23:59:59
//日
select to_char(to_date('2018-8-3', 'yyyy-mm-dd hh24:mi:ss')-3,'yyyy-mm-dd') from dual;//获取当前日期减去几就是从今天起往前推几天
//月
select to_char(add_months(to_date('2018-8-3', 'yyyy-mm-dd hh24:mi:ss'),-2),'yyyy-mm') from dual;//获取当前月,再传入负几就是从这月起往前推几月