HDU1002 A + B Problem II

• Problem Description
  I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

• Input
  The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

• Output
  For each test case, you should output two lines. The first line is “Case #:”, # means the number of the test case. The second line is the an equation “A + B = Sum”, Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

• Sample Input
  2
  1 2
  112233445566778899 998877665544332211

• Sample Output
  Case 1:
  1 + 2 = 3

  Case 2:
  112233445566778899 + 998877665544332211 = 1111111111111111110

• Author
  Ignatius.L

• 代码

#include
#include
void high_accuracy(char *a,char *b){
    int m,n,i=0,p=0;
    char c[1000001];
    m=strlen(a)-1; n=strlen(b)-1;
    for(i=0;m>=0||n>=0;i++,m--,n--){
        if(m>=0&&n>=0) c[i]=a[m]+b[n]-'0'+p;
        if(m>=0&&n<0) c[i]=a[m]+p;
        if(m<0&&n>=0) c[i]=b[n]+p;
        p=0;
        if(c[i]>'9') {
            c[i]=c[i]-10;
            p=1;
        }
    }
    if(p==1) printf("1");
    while(i--){
        printf("%c",c[i]);
    }
}
int main(){
    char a[10000]={'\0'},b[10000]={'\0'};
    int n=0,i=0;
    scanf("%d",&n);
    for(i=0;iscanf("%s %s",a,b);
        printf("Case %d:\n",i+1);
        printf("%s + %s = ",a,b);
        high_accuracy(a,b);
        if(i1) printf("\n\n");
        else printf("\n");
    }
    return 0;
}