hihoCoder 1051 补提交卡 最详细的解题报告

题目来源：补提交卡

解题思路：假设未提交程序的天数为：a1,a2,....,an，补交的张数为M。依次从a1,a2,....,an中去掉连续的 K 天（0<=K<=M），然后再来计算剩余数组中最长连续提交天数。

具体算法（Java版，直接AC）

 1 import java.util.Scanner;
 2 
 3 public class Main {
 4 
 5     //计算数组中最长连续提交天数
 6     public static int getMax(int[] array) {
 7         int[] copy = new int[array.length + 2];
 8         copy[0] = 0;
 9         copy[array.length + 1] = 101;
10         for (int i = 0; i < array.length; i++) {
11             copy[i + 1] = array[i];
12         }
13         int max = Integer.MIN_VALUE;
14         for (int i = 1; i < copy.length; i++) {
15             int sum = copy[i] - copy[i - 1] - 1;
16             max = max > sum ? max : sum;
17         }
18         return max;
19     }
20 
21     //从下标为start开始，删除长度为count个元素
22     public static int[] remove(int[] array, int count, int start) {
23         int[] copy = new int[array.length - count];
24         int index = 0;
25         for (int i = 0; i < start; i++) {
26             copy[index++] = array[i];
27         }
28         for (int i = start + count; i < array.length; i++) {
29             copy[index++] = array[i];
30         }
31         return copy;
32     }
33 
34     //计算使用k张补交卡后，最长连续提交天数
35     public static int solve(int[] array, int k) {
36         int max = Integer.MIN_VALUE;
37         for (int i = 0; i <= array.length - k; i++) {
38             int sum = getMax(remove(array, k, i));
39             max = max > sum ? max : sum;
40         }
41         return max;
42     }
43 
44     public static void main(String[] args) {
45         Scanner scanner = new Scanner(System.in);
46         int T = scanner.nextInt();
47         while (T > 0) {
48             int N = scanner.nextInt();
49             int M = scanner.nextInt();
50             int[] array = new int[N];
51             for (int i = 0; i < N; i++) {
52                 array[i] = scanner.nextInt();
53             }
54             int max = Integer.MIN_VALUE;
55             for (int i = 0; i <= M; i++) {
56                 int sum = solve(array, i);
57                 max = sum > max ? sum : max;
58             }
59             System.out.println(max);
60             --T;
61         }
62     }
63 }