python 文件合并小工具

工作中,小文件太多,所以就写个python脚本专门用来做文件合并,默认是10个文件合并成一个文件,话不多少,看代码

#!/usr/bin/python
# -*- coding: utf-8 -*-
__copyright__    = 'Copyright (c) 2017, newzol.cn'
__author__       = 'new zol'
__version__      = '1.0.0'
import os
import fnmatch
import datetime
DEPTH_FILE='' #新文件生成目录
SOURCE_FILE_NAME_PAT='ACCUM*' #文件名匹配

filelist = [] #文件保存列表
if __name__ == '__main__':
	print __copyright__
	print __version__
	print '开始处理目录:',os.getcwd()
	now = datetime.datetime.now()
	print("task start time:",now.strftime('%Y-%m-%d %H:%M:%S'))
	try:
		iTotalFile = 0
		iCount=0
		iNewfile=0
		bFlag = False
		global newfile
		srcfile = os.getcwd()
		filelist = os.listdir(srcfile)
		for filename in filelist:
			if not fnmatch.fnmatch(filename, 'ACCU*'):
				continue
			if os.path.isfile(os.path.join(srcfile,filename)):
				iTotalFile+=1
				if bFlag==False:
					newfile = open(os.path.join(DEPTH_FILE,filename),'w')
					bFlag = True
				fp = open(os.path.join(srcfile,filename),'r')
				for line in fp.readlines():
					newfile.write(line.replace('\n',''))
					newfile.write('\n')
					iCount += 1
				if iTotalFile % 10 == 0:
					newfile.close()
					iNewfile  += 1
					bFlag = False
		if iTotalFile % 10 != 0:
			newfile.close()
			iNewfile  += 1
		print '处理文件:',iTotalFile
		print '生成文件:',iNewfile
		print '总话单数:',iCount
		end = datetime.datetime.now()-now
		print '任务总耗时:',end.seconds,' 秒'

	except Exception as e:
		print(e)