spark+python快速入门实战小例子(PySpark)

1、集群测试实例

   代码如下：
from pyspark.sql import SparkSession

if __name__ == "__main__":
    spark = SparkSession\
            .builder\
            .appName("PythonWordCount")\
            .master("spark://mini1:7077") \
            .getOrCreate()
    spark.conf.set("spark.executor.memory", "500M")
    sc = spark.sparkContext
    a = sc.parallelize([1, 2, 3])
    b = a.flatMap(lambda x: (x,x ** 2))
    print(a.collect())
    print(b.collect())

   
   
   
   

   
   
   
   

    
    
    
    
1
    
    
    
    
2
    
    
    
    
3
    
    
    
    
4
    
    
    
    
5
    
    
    
    
6
    
    
    
    
7
    
    
    
    
8
    
    
    
    
9
    
    
    
    
10
    
    
    
    
11
    
    
    
    
12
   
   
   
   

   运行结果：

2、从文件中读取

   为了方便调试，这里采用本地模式进行测试

from py4j.compat import long
from pyspark.sql import SparkSession
def formatData(arr):
    # arr = arr.split(",")
    mb = (arr[0], arr[2])
    flag = arr[3]
    time = long(arr[1])
    # time = arr[1]
    if flag == "1":
          time = -time
    return (mb,time)

if name == “main”:
spark = SparkSession
.builder
.appName(“PythonWordCount”)
.master(“local”)
.getOrCreate()

sc = spark.sparkContext
# sc = spark.sparkContext
line = sc.textFile("D:\\code\\hadoop\\data\\spark\\day1\\bs_log").map(lambda x: x.split(','))
count = line.map(lambda x: formatData(x))
rdd0 = count.reduceByKey(lambda agg, obj: agg + obj)
# print(count.collect())
line2 = sc.textFile("D:\\code\\hadoop\\data\\spark\\day1\\lac_info.txt").map(lambda x: x.split(','))

rdd = count.map(lambda arr: (arr[0][1], (arr[0][0], arr[1])))
rdd1 = line2.map(lambda arr: (arr[0], (arr[1], arr[2])))

rdd3 = rdd.join(rdd1)
rdd4 =rdd0.map(lambda arr: (arr[0][0], arr[0][1], arr[1]))
    # .map(lambda arr: list(arr).sortBy(lambda arr1: arr1[2]).reverse)
rdd5 = rdd4.groupBy(lambda arr: arr[0]).values().map(lambda das: sorted(list(das), key=lambda x: x[2], reverse=True))
print(rdd5.collect())

• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10
• 11
• 12
• 13
• 14
• 15
• 16
• 17
• 18
• 19
• 20
• 21
• 22
• 23
• 24
• 25
• 26
• 27
• 28
• 29
• 30
• 31
• 32
• 33
• 34
• 35
• 36

   原文件数据：

   结果如下：

[[('18688888888', '16030401EAFB68F1E3CDF819735E1C66', 87600), ('18688888888', '9F36407EAD0629FC166F14DDE7970F68', 51200), ('18688888888', 'CC0710CC94ECC657A8561DE549D940E0', 1300)], [('18611132889', '16030401EAFB68F1E3CDF819735E1C66', 97500), ('18611132889', '9F36407EAD0629FC166F14DDE7970F68', 54000), ('18611132889', 'CC0710CC94ECC657A8561DE549D940E0', 1900)]]

   
   
   
   

   
   
   
   

    
    
    
    
1
   
   
   
   

3、读取文件并将结果保存至文件

from pyspark.sql import SparkSession
from py4j.compat import long

def formatData(arr):
# arr = arr.split(",")
mb = (arr[0], arr[2])
flag = arr[3]
time = long(arr[1])
# time = arr[1]
if flag == “1”:
time = -time
return (mb,time)

if name == “main”:
spark = SparkSession
.builder
.appName(“PythonWordCount”)
.master(“local”)
.getOrCreate()
sc = spark.sparkContext
line = sc.textFile(“D:\code\hadoop\data\spark\day1\bs_log”).map(lambda x: x.split(’,’))
rdd0 = line.map(lambda x: formatData(x))
rdd1 = rdd0.reduceByKey(lambda agg, obj: agg + obj).map(lambda t: (t[0][1], (t[0][0], t[1])))
line2 = sc.textFile(“D:\code\hadoop\data\spark\day1\lac_info.txt”).map(lambda x: x.split(’,’))
rdd2 = line2.map(lambda x: (x[0], (x[1], x[2])))
rdd3 = rdd1.join(rdd2).map(lambda x: (x[1][0][0], x[0], x[1][0][1], x[1][1][0], x[1][1][1]))

rdd4 = rdd3.groupBy(lambda x: x[0])
rdd5 = rdd4.mapValues(lambda das: sorted(list(das), key=lambda x: x[2], reverse=True)[:2])
print(rdd1.join(rdd2).collect())
print(rdd5.collect())
rdd5.saveAsTextFile("D:\\code\\hadoop\\data\\spark\\day02\\out1")
sc.stop()

• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10
• 11
• 12
• 13
• 14
• 15
• 16
• 17
• 18
• 19
• 20
• 21
• 22
• 23
• 24
• 25
• 26
• 27
• 28
• 29
• 30
• 31
• 32
• 33
• 34
• 35

   结果如下：

4、根据自定义规则匹配

import urllib
from pyspark.sql import SparkSession
def getUrls(urls):
    url = urls[0]
    parsed = urllib.parse.urlparse(url)
    return (parsed.netloc, url, urls[1])

if name == “main”:
spark = SparkSession
.builder
.appName(“PythonWordCount”)
.master(“local”)
.getOrCreate()
sc = spark.sparkContext
line = sc.textFile(“D:\code\hadoop\data\spark\day02\itcast.log”).map(lambda x: x.split(’\t’))
//从数据库中加载规则
arr = [“java.itcast.cn”, “php.itcast.cn”, “net.itcast.cn”]
rdd1 = line.map(lambda x: (x[1], 1))
rdd2 = rdd1.reduceByKey(lambda agg, obj: agg + obj)
rdd3 = rdd2.map(lambda x: getUrls(x))

for ins in arr:
    rdd = rdd3.filter(lambda x:x[0] == ins)
    result = rdd.sortBy(lambda x: x[2], ascending = False).take(2)
    print(result)
spark.stop()

• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10
• 11
• 12
• 13
• 14
• 15
• 16
• 17
• 18
• 19
• 20
• 21
• 22
• 23
• 24
• 25
• 26

   结果如下：

5、自定义类排序

from operator import gt
from pyspark.sql import SparkSession

class Girl:
def init(self, faceValue, age):
self.faceValue = faceValue
self.age = age

def __gt__(self, other):
    if other.faceValue == self.faceValue:
        return gt(self.age, other.age)
    else:
        return gt(self.faceValue, other.faceValue)

if name == “main”:
spark = SparkSession
.builder
.appName(“PythonWordCount”)
.master(“local”)
.getOrCreate()
sc = spark.sparkContext
rdd1 = sc.parallelize([(“yuihatano”, 90, 28, 1), (“angelababy”, 90, 27, 2), (“JuJingYi”, 95, 22, 3)])
rdd2 = rdd1.sortBy(lambda das: Girl(das[1], das[2]),False)
print(rdd2.collect())
sc.stop()

• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10
• 11
• 12
• 13
• 14
• 15
• 16
• 17
• 18
• 19
• 20
• 21
• 22
• 23
• 24
• 25
• 26
• 27

   结果如下：

6、JDBC

from pyspark import SQLContext
from pyspark.sql import SparkSession

if name == “main”:
spark = SparkSession
.builder
.appName(“PythonWordCount”)
.master(“local”)
.getOrCreate()
sc = spark.sparkContext
sqlContext = SQLContext(sc)
df = sqlContext.read.format(“jdbc”).options(url=“jdbc:mysql://localhost:3306/hellospark”,driver=“com.mysql.jdbc.Driver”,dbtable="(select * from actor) tmp",user=“root”,password=“123456”).load()
print(df.select(‘description’,‘age’).show(2))
# print(df.printSchema)

sc.stop()

• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10
• 11
• 12
• 13
• 14
• 15
• 16

   结果如下：