python:将一个文件转换为二进制文件(binary)

代码如下：

import sys

Numbers_In_Line = 16 #一行有几个数字
'''
* 将一个文件转换为二进制文件(binary)
* python3 tran_to_binary.py input_file out_file
* 20190713
'''
class TranStrToBinary():
	def tran_string_to_binary(self,buf):
		bytes_str = bytes(buf, encoding='utf-8')
		
		strbuf = ""
		for i in range(0,len(bytes_str)):
			tmp_str = str(hex(bytes_str[i]))
			tmp_str = tmp_str[2:].rstrip()
			if len(tmp_str) < 2:
				strbuf += "0" + tmp_str + " "
			else:
				strbuf += tmp_str + " "

		num = Numbers_In_Line * 3
		listBuf = list(strbuf)
		line_count = len(listBuf)
		if line_count / num > 0:
			for i in range(0,int(line_count / num)):
				pos = (i + 1) * num
				listBuf[pos-1] = '\n'
		strbuf = "".join(listBuf)
		return strbuf.rstrip()

	def tran_binary(self,inputFile,outputFile):
		try:
			with open(inputFile,"r") as fp_r:
				bufs = fp_r.read()
		except FileNotFoundError:
			print("The input files is not exist !")
			exit(2)
	
		print(self.tran_string_to_binary(bufs))
		with open(outputFile,"w") as fp_w:
			fp_w.write(self.tran_string_to_binary(bufs))
	
if __name__ == '__main__':
	print(str(sys.argv[0]) + " enter")
	
	tstb = TranStrToBinary()
	
	if len(sys.argv) != 3:
		print("The Bad Parameters !")
		exit(1)
	
	tstb.tran_binary(sys.argv[1],sys.argv[2])