HDU-A Mathematical Curiosity-求满足条件的数对数

问题及代码:

Problem I A Mathematical Curiosity

Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other)
Total Submission(s) : 12   Accepted Submission(s) : 4

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Problem Description

Given two integers n and m, count the number of pairs of integers (a,b) such that 0 < a < b < n and (a^2+b^2 +m)/(ab) is an integer.

This problem contains multiple test cases!

The first line of a multiple input is an integer N, then a blank line followed by N input blocks. Each input block is in the format indicated in the problem description. There is a blank line between input blocks.

The output format consists of N output blocks. There is a blank line between output blocks.

Input

You will be given a number of cases in the input. Each case is specified by a line containing the integers n and m. The end of input is indicated by a case in which n = m = 0. You may assume that 0 < n <= 100.

Output

For each case, print the case number as well as the number of pairs (a,b) satisfying the given property. Print the output for each case on one line in the format as shown below.

Sample Input

1

10 1
20 3
30 4
0 0

Sample Output

Case 1: 2
Case 2: 4
Case 3: 5


/*    
*Copyright (c)2015,烟台大学计算机与控制工程学院    
*All rights reserved.    
*文件名称:HDU.cpp    
*作    者:单昕昕    
*完成日期:2015年2月27日    
*版 本 号:v1.0        
*/ 
#include
using namespace std;
int main()
{
    int t;
    cin>>t;
    while(t--)
    {
        int n,m,a,b,i=1;
        while(cin>>n>>m && (n || m))
        {
            int count=0;
            for(a=1; a


运行结果:


HDU-A Mathematical Curiosity-求满足条件的数对数_第1张图片



知识点总结:
求满足条件的数对数。

学习心得:

就根据题目给定的两个条件列式计算循环查找记录就行了。

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