1.模拟linnux登录shell
#/bin/bash
echo -n "login:"
read name
echo -n "password:" read passwd if [ $name = "cht" -a $passwd = "abc" ];then echo "the host and password is right!" else echo "input is error!" fi
2.比较两个数大小
#/bin/bash
echo "please enter two number"
read a
read b if test $a -eq $b then echo "NO.1 = NO.2" elif test $a -gt $b then echo "NO.1 > NO.2" else echo "NO.1 < NO.2" fi
3.查找/root/目录下是否存在该文件
#/bin/bash
echo "enter a file name:"
read a
if test -e /root/$a then echo "the file is exist!" else echo "the file is not exist!" fi
4.for循环的使用
#/bin/bash
clear
for num in 1 2 3 4 5 6 7 8 9 10 do echo "$num" done
5.命令行输入
#/bin/bash
echo "Please enter a user:"
read a
b=$(whoami)
if test $a = $b then echo "the user is running." else echo "the user is not running." fi
6.删除当前目录下大小为0的文件
#/bin/bash
for filename in `ls`
do
if test -d $filename then b=0 else a=$(ls -l $filename | awk '{ print $5 }') if test $a -eq 0 then rm $filename fi fi done
7.如果/export/um_lpp_source下有文件,那么将其文件系统大小改为3G
#/bin/bash
while line=`ls /export/um_lpp_source`
do if test $line="" then echo "NULL" sleep 1 else echo $line chfs -a size=3G /export/um_lpp_source exit 0 fi done
8.测试IP地址
#/bin/bash
for i in 1 2 3 4 5 6 7 8 9 do echo "the number of $i computer is " ping -c 1 192.168.0.$i done 9.如果test.log的大小大于0,那么将/opt目录下的*.tar.gz文件 #/bin/sh a=2 while name="test.log" do sleep 1 b=$(ls -l $name | awk '{print $5}') if test $b -ge $a #then echo "OK" then `cp /opt/*.tar.gz .` exit 0 fi done
10.打印读取的内容,为下面的例子做准备
#/bin/bash
while read name
do
echo $name done
11.从0.sh中读取内容并打印
#/bin/bash
while read line
do
echo $line done < 0.sh
12.读取a.c中的内容并做加1运算
#/bin/bash
test -e a.c
while read line do a=$(($line+1)) done < a.c echo $a
13.普通无参数函数
#/bin/bash
p ()
{
echo "hello" } p
14.给函数传递参数
#/bin/bash
p_num ()
{
num=$1
echo $num } for n in $@ do p_num $n done
15.创建文件夹
#/bin/bash
while :
do
echo "please input file's name:" read a if test -e /root/$a then echo "the file is existing Please input new file name:" else mkdir $a echo "you aye sussesful!" break fi done
16.获取本机IP地址
#/bin/bash
ifconfig | grep "inet addr:" | awk '{ print $2 }'| sed 's/addr://g'
17.查找最大文件
#/bin/bash
a=0
for name in *.*
do b=$(ls -l $name | awk '{print $5}') if test $b -ge $a then a=$b namemax=$name fi done echo "the max file is $namemax"
18.查找当前网段内IP用户,重定向到ip.txt文件中
#/bin/bash
a=1
while :
do
a=$(($a+1)) if test $a -gt 255 then break else echo $(ping -c 1 192.168.0.$a | grep "ttl" | awk '{print $4}'| sed 's/://g') ip=$(ping -c 1 192.168.0.$a | grep "ttl" | awk '{print $4}'| sed 's/://g') echo $ip >> ip.txt fi done
19.打印当前用户
#/bin/bash
echo "Current User is :"
echo $(ps | grep "$$" | awk '{print $2}')
20.case语句练习
#!/bin/bash
clear
echo "enter a number from 1 to 5:"
read num
case $num in 1) echo "you enter 1" ;; 2) echo "you enter 2" ;; 3) echo "you enter 3" ;; 4) echo "you enter 4" ;; 5) echo "you enter 5" ;; *) echo "error" ;; esac
21.yes/no返回不同的结构
#!/bin/bash
clear
echo "enter [y/n]:"
read a
case $a in y|Y|Yes|YES) echo "you enter $a" ;; n|N|NO|no) echo "you enter $a" ;; *) echo "error" ;; esac
22.杀进程
#/bin/bash
pid=`ps -ef | grep '进程相关内容' | grep -v 'grep' | awk '{ print $2}'`
if [ -n "$pid" ]; then kill -9 $pid fi
23.内置命令的使用
#/bin/bash
clear
echo "Hello, $USER"
echo echo "Today 's date id `date`" echo echo "the user is :" who echo echo "this is `uname -s`" echo echo "that's all folks! "
24.打印无密码用户
#/bin/bash
echo "No Password User are :"
echo $(cat /etc/shadow | grep "!!" | awk 'BEGIN { FS=":" }{print $1}')
27.
#/bin/bash
clear
echo "Hello, $USER"
echo echo "Today 's date id `date`" echo echo "the user is :" who echo echo "this is `uname -s`" echo echo "that's all folks! "
28.检查端口号是否已启动
#!/bin/bash
n=1
echo "检查xxx服务..."
while true do if test $n -gt 20 then echo "xxx服务启动失败" break fi sleep 5 n=$(($n+1)) port=`netstat -antp | grep "0.0.0.0:8080"` if [ ${#port} -gt 3 ]; then echo "xxx服务已经启动" break; fi done
练习一:写一个脚本
1.设定变量FILE的值为/etc/passwd
2.依次向/etc/passwd中的每个用户问好,并且说出对方的ID是什么
形如:(提示:LINE=`wc -l /etc/passwd | cut -d" " -f1`)
Hello,root,your UID is 0.
3.统计一个有多少个用户
答案一:#!/bin/bash
file="/etc/passwd"
LINES=`wc -l $file | cut -d" " -f1`
for I in `seq 1 $LINES`;do
userid=`head -$I $file | tail -1 |cut -d: -f3`
username=`head -$I $file | tail -1 |cut -d: -f1`
echo "hello $username,your UID is $userid"
done
echo "there are $LINES users"
答案二:#!/bin/bash
file=/etc/passwd
let num=0
for I in `cat $file`;do
username=`echo "$I" | cut -d: -f1`
userid=`echo "$I" | cut -d: -f3`
echo "Hello,$username,your UID is $userid"
num=$[$num+1]
done
echo "there are $num users"
练习二:写一个脚本
1.切换工作目录至/var
2.依次向/var目录中的每个文件或子目录问好,形如:
(提示:for FILE in /var/*;或for FILE in `ls /var`;)
Hello,log
3.统计/var目录下共有多个文件,并显示出来
答案:#!/bin/bash
cd /var
let num=0
for I in `ls /var/*`;do
echo "hello $I"
num=$[$num+1]
done
echo "the number of files is $num"
练习三:写一个脚本
1.设定变量file的值为/etc/passwd
2.使用循环读取文件/etc/passwd的第2,4,6,10,13,15行,并显示其内容
3.把这些行保存至/tmp/mypasswd文件中
答案:#!/bin/bash
file="/etc/passwd"
for I in 2 4 6 10 13 15;do
exec 3>/tmp/mypasswd
line=`head -$I $file | tail -1`
echo "$line"
echo "$line" >&3
exec 3>&-
done
1.设定变量FILE的值为/etc/passwd
2.依次向/etc/passwd中的每个用户问好,并且说出对方的ID是什么
形如:(提示:LINE=`wc -l /etc/passwd | cut -d" " -f1`)
Hello,root,your UID is 0.
3.统计一个有多少个用户
答案一:#!/bin/bash
file="/etc/passwd"
LINES=`wc -l $file | cut -d" " -f1`
for I in `seq 1 $LINES`;do
userid=`head -$I $file | tail -1 |cut -d: -f3`
username=`head -$I $file | tail -1 |cut -d: -f1`
echo "hello $username,your UID is $userid"
done
echo "there are $LINES users"
答案二:#!/bin/bash
file=/etc/passwd
let num=0
for I in `cat $file`;do
username=`echo "$I" | cut -d: -f1`
userid=`echo "$I" | cut -d: -f3`
echo "Hello,$username,your UID is $userid"
num=$[$num+1]
done
echo "there are $num users"
练习二:写一个脚本
1.切换工作目录至/var
2.依次向/var目录中的每个文件或子目录问好,形如:
(提示:for FILE in /var/*;或for FILE in `ls /var`;)
Hello,log
3.统计/var目录下共有多个文件,并显示出来
答案:#!/bin/bash
cd /var
let num=0
for I in `ls /var/*`;do
echo "hello $I"
num=$[$num+1]
done
echo "the number of files is $num"
练习三:写一个脚本
1.设定变量file的值为/etc/passwd
2.使用循环读取文件/etc/passwd的第2,4,6,10,13,15行,并显示其内容
3.把这些行保存至/tmp/mypasswd文件中
答案:#!/bin/bash
file="/etc/passwd"
for I in 2 4 6 10 13 15;do
exec 3>/tmp/mypasswd
line=`head -$I $file | tail -1`
echo "$line"
echo "$line" >&3
exec 3>&-
done
练习四:写一个脚本
传递两个整数给脚本,让脚本分别计算并显示这两个整数的和,差,积,商
答案如下:vim test.sh
#!/bin/bash
echo "first number $1" (表示输出第一个数)
答案如下:vim test.sh
#!/bin/bash
echo "first number $1" (表示输出第一个数)
echo "second number $2" (表示输出第二个数)
echo " $(($1+$2))" (输出两数之和)
echo "$[$1-$2]" (输出两数之差)
echo "$[$1*$2]" (输出两数之积)
echo " $(($1+$2))" (输出两数之和)
echo "$[$1-$2]" (输出两数之差)
echo "$[$1*$2]" (输出两数之积)
echo "$[$1/$2]" (输出两数之商)
:wq (表示保存并退出vi编辑器)
chmod +x test.sh (给test.sh执行的权限)
./test.sh 2 3 (传递两个参数并执行脚本
:wq (表示保存并退出vi编辑器)
chmod +x test.sh (给test.sh执行的权限)
./test.sh 2 3 (传递两个参数并执行脚本
作业一:写一个脚本:
1.创建目录/tmp/scripts
2.切换工作目录至此目录中
3.复制/etc/pam.d目录至当前目录,并重命名为test
4.将当前目录的test及其里面的文件和子目录的属主改为redhat
5.将test及其子目录中的文件的其它用户的权限改为没有任何权限
答案:
#!/bin/bash
mkdir -v /tmp/scripts
cd /tmp/scripts
cp -r /etc/pam.d ./test
chown -R redhat ./test
chmod -R o=--- ./test
#!/bin/bash
mkdir -v /tmp/scripts
cd /tmp/scripts
cp -r /etc/pam.d ./test
chown -R redhat ./test
chmod -R o=--- ./test
作业二:写一个脚本
1.显示当前系统日期和时间,而后创建目录/tmp/lstest
2.切换工作目录至/tmp/lstest
3.创建目录a1d,b56e,6test
4.创建空文件xy,x2y,732
5.列出当前目录下以a,x或者6开头的文件或目录
6.列出当前目录下以字母开头,后跟一个任意数字,而后跟任意长度字符的文件或目录
答案:
#!/bin/bash
date
mkdir -pv /tmp/lstest
cd /tmp/lstest
mkdir a1d b56e 6test
touch xy x2y 732
ls [ax6]*
ls [[:alpha:]][[:digit:]]*
#!/bin/bash
date
mkdir -pv /tmp/lstest
cd /tmp/lstest
mkdir a1d b56e 6test
touch xy x2y 732
ls [ax6]*
ls [[:alpha:]][[:digit:]]*
作业三:写一个脚本
添加10个用户user1到user10,但要求只有用户不存在的情况下才能添加
答案:
#!/bin/bash
for I in `seq 1 10`;do
cut -d: -f1 /etc/passwd |grep "user$I" 2>>/tmp/etc.err || useradd user$I
done
作业四:写一个脚本
通过ping命令测试192.168.0.151到192.168.0.254之间的所有主机是否在线
如果在线,就显示“ip is up”
如果不在线,就显示“ip is down”
答案: #!/bin/bash
for I in `seq 151 254`;do
ping -c1 -w1 192.168.0.$I &>/dev/null && echo "192.168.0.$I is up" || echo "192.168.0.$I is down"
done
1、实现批量添加20个用户,用户名为user1-20,密码为user+123
#!/bin/bash count=$1 if [ -n "$count" ] then for ((i=1;i<=$count;i++)) do useradd -d /home/user_$i -s /bin/bash user_$i; echo user_"$i"123 |passwd --stdin user_$i; done else echo "$count is empty" fi
2、100个数相加,最大值,最小值
#!/bin/bash sum=0 for i in `seq 0 1 99` do echo "第"$i"次" read -p "请输入数字" n a=$n sum=$[$sum+$n] done echo "最大值" echo ${a}|sed 's//\n/g'|sort -r|sed -n '1'p echo "最小值" echo ${a}|sed 's//\n/g'|sort -n|sed -n '1'p echo $sum ~