- 我用的SQL语句:
- delete from fp_sgfpxx
where fphm in (select fphm from fp_sgfpxx group by fphm having count(fphm) > 1)
and rowid not in (select min(rowid) from fp_sgfpxx group by fphm having count(fphm )>1) - 删除重复的发票号码
- 查询同一表内多字段同时重复记录的SQL语句
- 来自:7th string
- 比如现在有一人员表 (表名:peosons)
- 若想将姓名、身份证号、住址这三个字段完全相同的记录查询出来 select p1.* from persons p1,persons p2 where p1.id<>p2.id and p1.cardid = p2.cardid and p1.pname = p2.pname and p1.address = p2.address
- 可以实现上述效果.
- 几个删除重复记录的SQL语句
- 1.用rowid方法
- 2.用group by方法
- 3.用distinct方法
- 1。用rowid方法
- 据据Oracle带的rowid属性,进行判断,是否存在重复,语句如下:
- 查数据:
- select * from table1 a where rowid !=(select max(rowid)
- from table1 b where a.name1=b.name1 and a.name2=b.name2......)
- 删数据:
- delete from table1 a where rowid !=(select max(rowid)
- from table1 b where a.name1=b.name1 and a.name2=b.name2......)
- 2.group by方法
- 查数据:
- select count(num), max(name) from student --列出重复的记录数,并列出他的name属性
- group by num
- having count(num) >1 --按num分组后找出表中num列重复,即出现次数大于一次
- 删数据:
- delete from student
- group by num
- having count(num) >1
- 这样的话就把所有重复的都删除了。
- 3.用distinct方法 -对于小的表比较有用
- create table table_new as select distinct * from table1 minux
- truncate table table1;
- insert into table1 select * from table_new;
- 查询及删除重复记录的方法大全
- 1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
- select * from people
- where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
- 2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
- delete from people
- where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
- and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)
- 3、查找表中多余的重复记录(多个字段)
- select * from vitae a
- where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
- 4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录
- delete from vitae a
- where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
- and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
- 5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
- select * from vitae a
- where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
- and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
- (二)
- 比方说
- 在A表中存在一个字段“name”,
- 而且不同记录之间的“name”值有可能会相同,
- 现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
- Select Name,Count(*) From A Group By Name Having Count(*) > 1
- 如果还查性别也相同大则如下:
- Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1
- (三)
- 方法一
- declare @max integer,@id integer
- declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >; 1
- open cur_rows
- fetch cur_rows into @id,@max
- while @@fetch_status=0
- begin
- select @max = @max -1
- set rowcount @max
- delete from 表名 where 主字段 = @id
- fetch cur_rows into @id,@max
- end
- close cur_rows
- set rowcount 0
- 方法二
- "重复记录"有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。
- 1、对于第一种重复,比较容易解决,使用
- select distinct * from tableName
- 就可以得到无重复记录的结果集。
- 如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除
- select distinct * into #Tmp from tableName
- drop table tableName
- select * into tableName from #Tmp
- drop table #Tmp
- 发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。
- 2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下
- 假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集
- select identity(int,1,1) as autoID, * into #Tmp from tableName
- select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
- select * from #Tmp where autoID in(select autoID from #tmp2)
- 最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)
- (四)
- 查询重复
- select * from tablename where id in (
- select id from tablename
- group by id
- having count(id) > 1
- )
- ===========================
-
在几千条记录里,存在着些相同的记录,如何能用SQL语句,删除掉重复的呢?谢谢!
1、查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断
select * from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
2、删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录
delete from people
where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1)
and rowid not in (select min(rowid) from people group by peopleId having count(peopleId )>1)
3、查找表中多余的重复记录(多个字段)
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
4、删除表中多余的重复记录(多个字段),只留有rowid最小的记录
delete from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
5、查找表中多余的重复记录(多个字段),不包含rowid最小的记录
select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)
比方说在A表中存在一个字段“name”,而且不同记录之间的“name”值有可能会相同,
现在就是需要查询出在该表中的各记录之间,“name”值存在重复的项;
Select Name,Count(*) From A Group By Name Having Count(*) > 1
如果还查性别也相同大则如下:
Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 12.group by方法
查数据:
select count(num), max(name) from student --列出重复的记录数,并列出他的name属性
group by num
having count(num) >1 --按num分组后找出表中num列重复,即出现次数大于一次
删数据:
delete from student
group by num
having count(num) >1
这样的话就把所有重复的都删除了。
3.用distinct方法 -对于小的表比较有用
create table table_new as select distinct * from table1 minux
truncate table table1;
insert into table1 select * from table_new;
delete select a.* from FLRK1 a inner join FLRK1 b on a.记录号=b.记录号 and
(a.[ID]=b.[ID] and a.入库日期=b.入库日期 and a.操作时间=b.操作时间)
delete from FLRK1 where 记录号 in
(select min(记录号) from FLRK1 group by 记录号 having count(记录号)>1)
A表结构:
ID RQ SJ C
--------------------------------------------
1 2005-07-14 14:20:50 A1
2 2005-02-15 05:12:23 A1
3 2005-07-14 14:20:50 A1
4 2005-06-16 16:16:16 A2
5 2005-06-16 16:16:16 A2
6 2005-05-18 05:10:35 A3
7 2005-02-15 05:12:23 A1
--------------------------------------------
求SQL语句一条,把表A中 RQ,SJ,C 三个字段有相同的重复记录删除.
得到的结果:
ID RQ SJ C
--------------------------------------------
1 2005-07-14 14:20:50 A1
2 2005-02-15 05:12:23 A1
4 2005-06-16 16:16:16 A2
6 2005-05-18 05:10:35 A3
--------------------------------------------
Delete from A Where ID Not In (Select Min(ID) from A Group By RQ,SJ,C )
Delete a from tb a inner join tb as b on a.fid
delete from A t
where exists(select 1 from A where ID
方法一
declare @max integer,@id integer
declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) > 1
open cur_rows
fetch cur_rows into @id,@max
while fetch_status=0
begin
select @max = @max -1
set rowcount @max
delete from 表名 where 主字段 = @id
fetch cur_rows into @id,@max
end
close cur_rows
set rowcount 0
方法二
有两个意义上的重复记录,一是完全重复的记录,也即所有字段均重复的记录,二是部分关键字段重复的记录,比如Name字段重复,而其他字段不一定重复或都重复可以忽略。
1、对于第一种重复,比较容易解决,使用
select distinct * from tableName
就可以得到无重复记录的结果集。
如果该表需要删除重复的记录(重复记录保留1条),可以按以下方法删除
select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp
发生这种重复的原因是表设计不周产生的,增加唯一索引列即可解决。
2、这类重复问题通常要求保留重复记录中的第一条记录,操作方法如下
假设有重复的字段为Name,Address,要求得到这两个字段唯一的结果集
select identity(int,1,1) as autoID, * into #Tmp from tableName
select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
select * from #Tmp where autoID in(select autoID from #tmp2)
最后一个select即得到了Name,Address不重复的结果集(但多了一个autoID字段,实际写时可以写在select子句中省去此列)