最小费用最大流( 洛谷3381)

题目链接:https://www.luogu.org/problemnew/show/P3381

思路:模板题,改都不带改的

#pragma GCC optimize(2)
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
#include 
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
const ll inff = 0x3f3f3f3f3f3f3f3f;
#define FOR(i,a,b) for(int i(a);i<=(b);++i)
#define FOL(i,a,b) for(int i(a);i>=(b);--i)
#define REW(a,b) memset(a,b,sizeof(a))
#define inf int(0x3f3f3f3f)
#define si(a) scanf("%d",&a)
#define sl(a) scanf("%lld",&a)
#define sd(a) scanf("%lf",&a)
#define ss(a) scanf("%s",a)
#define mod ll(6666666)
#define pb push_back
#define eps 1e-6
#define lc d<<1
#define rc d<<1|1
#define Pll pair
#define P pair
#define pi acos(-1)
const int N=1e4+7;
struct edge{int to,cap,cost,rev;};
vectorg[N];
int h[N],d[N],pre[N],prv[N],n,m,res,s,t,flow;
void add(int from,int to,int cap,int cost)
{
    g[from].pb(edge{to,cap,cost,(int)g[to].size()});
    g[to].pb(edge{from,0,-cost,(int)g[from].size()-1});
}
void slove(int s,int t,int f,int n)
{
    //int res=0;
    fill(h,h+n+1,0);
    while(f>0)
    {
        priority_queue,greater

> q; fill(d,d+n+1,inf); d[s]=0; q.push(P(0,s)); while(!q.empty()) { P p=q.top();q.pop(); int v=p.second; if(d[v]0&&d[e.to]>d[v]+e.cost+h[v]-h[e.to]) { d[e.to]=d[v]+e.cost+h[v]-h[e.to]; prv[e.to]=v;pre[e.to]=i; q.push(P(d[e.to],e.to)); } } } if(d[t]==inf) break; FOR(i,0,n) h[i]+=d[i]; int d=f; for(int i=t;i!=s;i=prv[i]) d=min(d,g[prv[i]][pre[i]].cap); f-=d,flow+=d; res+=d*h[t]; for(int i=t;i!=s;i=prv[i]) { edge &e=g[prv[i]][pre[i]]; e.cap-=d; g[i][e.rev].cap+=d; } } //return res; } int main() { cin.tie(0); cout.tie(0); cin>>n>>m>>s>>t; int x,y,z,q; FOR(i,1,m) { si(x),si(y),si(z),si(q); add(x,y,z,q); } slove(s,t,inf,n); cout<

 

你可能感兴趣的:(网络流)