深度学习基础 - 累加符号和连乘符号

深度学习基础 - 累加符号和连乘符号

flyfish

累加符号 其他名字 Sigma Notation 、Summation Notation

示例1

∑ i = 1 5 i = 1 + 2 + 3 + 4 + 5 \displaystyle \begin{aligned} &\sum_{i=1}^{5} i\\ &=1+2+3+4+5 \end{aligned} i=15i=1+2+3+4+5

示例2

∑ i = 3 7 i = 3 + 4 + 5 + 6 + 7 \displaystyle \begin{aligned} &\sum_{i=3}^{7} i\\ &=3+4+5+6+7 \end{aligned} i=37i=3+4+5+6+7

示例3

∑ i = 2 5 2 i = 2 ( 2 ) + 2 ( 3 ) + 2 ( 4 ) + 2 ( 5 ) = 4 + 6 + 8 + 10 \displaystyle \begin{aligned} &\sum_{i=2}^{5} 2 i\\ &=2(2)+2(3)+2(4)+2(5)\\ &=4+6+8+10 \end{aligned} i=252i=2(2)+2(3)+2(4)+2(5)=4+6+8+10

示例4

∑ j = 1 4 j x = 1 x + 2 x + 3 x + 4 x \displaystyle \begin{aligned} &\sum_{j=1}^{4} j x\\ &=1 x+2 x+3 x+4 x \end{aligned} j=14jx=1x+2x+3x+4x

示例5

∑ i = 1 2 ∑ j = 4 6 ( 3 i j ) = ∑ i = 1 2 ( 3 i ⋅ 4 + 3 i ⋅ 5 + 3 i ⋅ 6 ) = ( 3 ⋅ 1 ⋅ 4 + 3 ⋅ 1 ⋅ 5 + 3 ⋅ 1 ⋅ 6 ) + ( 3 ⋅ 2 ⋅ 4 + 3 ⋅ 2 ⋅ 5 + 3 ⋅ 2 ⋅ 6 ) \displaystyle \begin{aligned} &\sum_{i=1}^{2} \sum_{j=4}^{6}(3 i j)\\ &=\sum_{i=1}^{2}(3 i \cdot 4+3 i \cdot 5+3 i \cdot 6)\\ &=(3 \cdot 1 \cdot 4+3 \cdot 1 \cdot 5+3 \cdot 1 \cdot 6)+(3 \cdot 2 \cdot 4+3 \cdot 2 \cdot 5+3 \cdot 2 \cdot 6) \end{aligned} i=12j=46(3ij)=i=12(3i4+3i5+3i6)=(314+315+316)+(324+325+326)

示例6

∑ k = 1 ∞ ( k + 1 ) 3 = 2 3 + 3 3 + ⋯ n 3 + ⋯ \displaystyle \sum_{k=1}^{\infty}(k+1)^{3}=2^{3}+3^{3}+\cdots n^{3}+\cdots k=1(k+1)3=23+33+n3+

连乘符号 其他名字 Pi Notation、Product Notation

示例1

∏ i = 3 7 i = ( 3 ) ( 4 ) ( 5 ) ( 6 ) ( 7 ) \displaystyle \begin{aligned} &\prod_{i=3}^{7} i\\ &=(3)(4)(5)(6)(7) \end{aligned} i=37i=(3)(4)(5)(6)(7)

示例2

∏ i = 1 6 i 2 = ( 1 ) ( 4 ) ( 9 ) ( 16 ) ( 25 ) ( 36 ) \displaystyle \prod_{i=1}^{6} i^{2}=(1)(4)(9)(16)(25)(36) i=16i2=(1)(4)(9)(16)(25)(36)

示例3

∏ i = 1 2 ∏ j = 4 6 ( 3 i j ) = ∏ i = 1 2 ( ( 3 i ⋅ 4 ) ( 3 i ⋅ 5 ) ( 3 i ⋅ 6 ) ) = ( ( 3 ⋅ 1 ⋅ 4 ) ( 3 ⋅ 1 ⋅ 5 ) ( 3 ⋅ 1 ⋅ 6 ) ) ( ( 3 ⋅ 2 ⋅ 4 ) ( 3 ⋅ 2 ⋅ 5 ) ( 3 ⋅ 2 ⋅ 6 ) ) \displaystyle \begin{aligned} &\prod_{i=1}^{2} \prod_{j=4}^{6}(3 i j)\\ &=\prod_{i=1}^{2}((3 i \cdot 4)(3 i \cdot 5)(3 i \cdot 6))\\ &=((3 \cdot 1 \cdot 4)(3 \cdot 1 \cdot 5)(3 \cdot 1 \cdot 6))((3 \cdot 2 \cdot 4)(3 \cdot 2 \cdot 5)(3 \cdot 2 \cdot 6)) \end{aligned} i=12j=46(3ij)=i=12((3i4)(3i5)(3i6))=((314)(315)(316))((324)(325)(326))

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