【LintCode】637. 检查缩写字（熟悉字符串）

描述

中文English

给定一个非空字符串 word 和缩写 abbr，返回字符串是否可以和给定的缩写匹配。
比如一个 “word” 的字符串仅包含以下有效缩写：

["word", "1ord", "w1rd", "wo1d", "wor1", "2rd", "w2d", "wo2", "1o1d", "1or1", "w1r1", "1o2", "2r1", "3d", "w3", "4"]

样例

样例 1:

输入 : s = "internationalization", abbr = "i12iz4n"
输出 : true

样例 2:

输入 : s = "apple", abbr = "a2e"
输出 : false

 

public class Solution {
    /**
     * @param word: a non-empty string
     * @param abbr: an abbreviation
     * @return: true if string matches with the given abbr or false
     */
    public boolean validWordAbbreviation(String word, String abbr) {
        // write your code here
        int i = 0;
        int j = 0;
        while (i < word.length() && j < abbr.length()) {
            if (word.charAt(i) == abbr.charAt(j)) {
                i ++;
                j ++;
            } else if (abbr.charAt(j) > '0' && abbr.charAt(j) <= '9') {
                int start = j;
                while(j < abbr.length() && Character.isDigit(abbr.charAt(j))) {
                    j ++;
                }
                i += Integer.valueOf(abbr.substring(start, j));
            } else {
                return false;
            } 
        }
        return (i == word.length()) && (j == abbr.length());
    }
}