C#JSON文件操作

首先声明，博主采用的是vs2015

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1.配置json环境：

配置json环境有俩种方法，一种是直接去官网下载包，导进vs中，一种是直接在vs中在线安装，自动配置(这里介绍第二种,直接上图)

在工程视图中右键引用，点击管理NuGet程序包

搜索litjson，然后下载安装即可

创建工程文件如图：

json.txt:

[
{"id":2,"name":"天下无双","damage":123},
{"id":3,"name":"天下无贼","damage":23},
{"id":4,"name":"咫尺天涯","damage":900}
]

Skill.cs:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace JSON解析
{
    class Skill
    {
        public int id;
        public int damage;
        public string name;

        public override string ToString()
        {
            return string.Format("Id:{0},Damage:{1},Name:{2}", id, damage, name);
        }
    }
}

Program.cs:

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using LitJson;

namespace JSON解析
{
    class Program
    {
        static void Main(string[] args)
        {
            List skilllList = new List();
            //使用jsonmapper去解析json文本
            //jsondata代表一个数组或者一个对象
            //在这里jsondata代表一个数组
            JsonData jsonData = JsonMapper.ToObject(File.ReadAllText("json.txt"));
            foreach (JsonData tempData in jsonData)//这里的temp代表一个对象
            {
                Skill skill = new Skill();
                JsonData idValue = tempData["id"];//通过字符索引器可以取得键值对的值
                JsonData nameValue = tempData["name"];
                JsonData damageValue = tempData["damage"];
                int id = int.Parse(idValue.ToString());
                int damage = int.Parse(damageValue.ToString());
                Console.WriteLine(id + ":" + nameValue.ToString() + ":" + damage);
                skill.id = id;
                skill.damage = damage;
                skill.name = nameValue.ToString();
                skilllList.Add(skill);
            }
       }
     }
  }

第二种简单方法Program.cs:

 using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using LitJson;

namespace JSON解析
{
    class Program
    {
        static void Main(string[] args)
        {
             //使用泛型去解析json文件
            Skill[] skillArray = JsonMapper.ToObject(File.ReadAllText("json.txt"));//使用这种方法，泛型类的字段，属性必须为public，而且字段名，顺序必须与json文件中对应
            foreach (var temp in skillArray)
            {
                Console.WriteLine(temp);
            }

            List skilllList = JsonMapper.ToObject>(File.ReadAllText("json.txt"));
            foreach (var temp in skilllList)
            {
                Console.WriteLine(temp);
            }
       }
     }
  }

json文件与类的转化:

敌人.txt:

{
"Name":"lala",
 "Level":99,
 "Age":18,
 "SkillList":[
{"id":2,"name":"天下无双","damage":123},
{"id":3,"name":"天下无贼","damage":23},
{"id":4,"name":"咫尺天涯","damage":900}
]
}

Player.cs:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace JSON解析
{
    class Player
    {
        public string Name { get; set; }
        public  int Level { get; set; }
        public  int Age { get; set; }
        public List SkillList { get; set; }

        public override string ToString()
        {
            return string.Format("Name:{0},Level:{1},Age:{2},SkillList:{3}", Name, Level, Age,SkillList);
        }
    }
}

Program.cs:

using System;
using System.Collections.Generic;
using System.IO;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using LitJson;

namespace JSON解析
{
    class Program
    {
        static void Main(string[] args)
        {
            Player p = JsonMapper.ToObject(File.ReadAllText("敌人.txt"));//json文件向类的转化
            Console.WriteLine(p);

            //将一个对象转换成json
            Player p = new Player();
            p.Name = "www";
            p.Level = 99;
            p.Age = 14;
            string s = JsonMapper.ToJson(p);
            Console.WriteLine(s);
        }
    }
}