将字符串中的字母倒序,数字顺序保持不变

/**
 * 
 * convert the characters not the number in the string
 *
 */
public class Demo 
{
	public static void main(String[] args)
	{
		Demo demo = new Demo();
		String inputStr = "I am a student no12 3456 1234";
		StringBuffer buffer = new StringBuffer();
		demo.vConvertMsg(inputStr,buffer);
		System.out.print(buffer);
	}
	public void vConvertMsg(String sInputStr,StringBuffer OutputStr)
	{
		String[] str = sInputStr.split(" ");
		int len = str.length;
		
		for (int i = 0;i < len;++i)
		{
			
			char[] c = str[i].toCharArray();
			String string = Char(c);
			OutputStr.append(string + " ");
		}
	}
	
	String Char(char[] c)
	{

		int length = c.length;
		StringBuffer a = new StringBuffer("");
		StringBuffer all = new StringBuffer("");
		for (int j = 0;j < length;++j)
		{
			boolean isNum = Character.isDigit(c[j]);
			if (!isNum)
			{
				a.append(c[j]);
			}
			else
			{
				if(a.length() != 0){
					all.append(a.reverse());
					//System.out.println(a.length());
					a.delete(0, a.length());
				}
				all.append(c[j]);
			}
		}
		all.append(a.reverse());
		String buffer =all.toString();
		return buffer;
	}
	
}

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