在SQL SERVER中,XML查询可以指定RAW,AUTO,EXPLICIT,PATH。本文用一些实例介绍SQL SERVER中指定AUTO的XML查询。
with TestXml
as
(
select 1 as id,N'LeeWhoeeUniversity' as name
union all
select 2,N'DePaul'
union all
select 3 ,null
)
select id,name from testxml for xml auto
结果:
下面看多表的查询(片断2):
with [order]
as
(
select 122 as orderid, 1 as productid,10 as quantity
union all
select 123,1 as productid,100 as quantity
union all
select 124,2,20
union all
select 125,3 ,5
),
product
as
(
select 1 as id,N'LeeWhoeeUniversity' as name
union all
select 2,N'DePaul'
)
select * from product,[order] where [order].productid=product.id for xmlauto
结果:
如果把product和order换一下位置,片断3:
with [order]
as
(
select 122 as orderid, 1 as productid,10 as quantity
union all
select 123,1 as productid,100 as quantity
union all
select 124,2,20
union all
select 125,3 ,5
),
product
as
(
select 1 as id,N'LeeWhoeeUniversity' as name
union all
select 2,N'DePaul'
)
select * from [order],product where [order].productid=product.id for xml auto
结果:
当然,AUTO模式同样也可以指定ELEMENTS,BINARY BASE64,同RAW。(SQL SERVER中XML查询:FOR XML指定RAW)
AUTO 模式根据查询决定返回的 XML 的形式。 在决定嵌套元素的方式时,AUTO 模式试探方法会比较相邻行中的列值。ntext、text、image 和xml 类型以外的所有类型的列都会进行比较。 (n)varchar(max) 和varbinary(max) 类型的列也会进行比较。
上面的第一个指定AUTO的SQL语句(片断2)结果集为:
id name orderid productid quantity
1 LeeWhoeeUniversity 122 1 10
1 LeeWhoeeUniversity 123 1 100
2 DePaul 124 2 20
AUTO 模式试探方法将比较表 product 的所有值(Id 列和 Name 列)。因为前两行的 Id 列和 Name 列具有相同的值,所以向结果中添加了一个具有两个
如果把Name 列改为 text 类型。 AUTO 模式试探方法不比较此类型的值, 而是认为这些值不相同。
见下面代码片断4:
declare @order table(orderid int,productid int,quantity int)
declare @product table(id int,name text)
insert into @order
select 122 as orderid, 1 as productid,10 as quantity
union all
select 123,1 as productid,100 as quantity
union all
select 124,2,20
union all
select 125,3 ,5
insert into @product
select 1 ,N'LeeWhoeeUniversity'
union all
select 2,N'DePaul'
select * from @product as product,@order as [order] where [order].productid=product.id for xmlauto
结果:
上面结果中name同为LeeWhoeeUniversity的项被分成两个product。
再看第一个指定AUTO的SQL语句,但是更改了orderid为使其结果集中相同id和name的项不连在一起:
with [order]
as
(
select 122 as orderid, 1 as productid,10 as quantity
union all
select 125,1 as productid,100 as quantity
union all
select 123,2,20
union all
select 124,3 ,5
),
product
as
(
select 1 as id,N'LeeWhoeeUniversity' as name
union all
select 2,N'DePaul'
)
select * from product,[order] where [order].productid=product.id
order by orderid
结果:
id name orderid productid quantity
1 LeeWhoeeUniversity 122 1 10
2 DePaul 123 2 20
1 LeeWhoeeUniversity 125 1 100
然后进行指定AUTO的XML查询(即语句上添加for xml auto),AUTO模式试探将生成以下结果:
这样相同id和name的product没有连在一起。