LeetCode（237）Delete Node in a Linked List

题目

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

分析

题目要求删除指定结点，但是给定参数只有目标结点。
转移思维，改成拷贝目标结点后结点的值，然后删除目标结点的后一结点。

AC代码

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    void deleteNode(ListNode* node) {
        if (node == NULL)
            return;
        else if(node->next != NULL){ 
            //只给出一个要删除的结点，转移思维，改成拷贝目标结点后结点的值，然后删除目标结点的后一结点
            node->val = node->next->val;
            node->next = node->next->next;
        }
        else{
            return;
        }
    }
};

GitHub 测试程序源码