java Web中页面跳转方式之请求转发

java Web中页面跳转方式之请求转发

1、在一个请求中跨越多个Servlet

2、多个Servlet在一个请求中，他们共享request对象。就是在Servlet01中setAttribute（）保存数据在Servlet02中由getAttribute（）取出数据

3、在Servlet01转发到Servlet02，那么整个请求都是由Servlet02来完成，Servlet01不再插手

4、Servlet01 包含Servlet02，那么两个Servlet共同完成请求

5、请求转发和请求包含都需要使用一个对象RequestDispatcher。

 

Servlet01:

public class DemoServlet01 extends HttpServlet {
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    }

    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        //从数据库获取数据
        UserService service = new UserService();
        List userList = service.getUserList();
        //把数据放到request对象中
        request.setAttribute("userList", userList);
        //获取重定向对象
        RequestDispatcher requestDispatcher = request.getRequestDispatcher("/DemoServlet03");
        //重定向对象执行操作
        requestDispatcher.forward(request, response);
    }
}

Servlet02:

public class DemoServlet02 extends HttpServlet {
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

    }

    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        //从request中取出数据
        List list = (List) request.getAttribute("userList");
        //响应到请求的客户端
        response.setContentType("text/html;charset=utf-8");
        for (User user : list) {
            response.getWriter().print(user);
        }

    }
}

 

附图一张:

 

html页面跳转: <a href="http://www.baidu.comd">百度

js页面跳转: window.open(url); location.href=url

posted @ 2016-07-04 19:51 青衫仗剑 阅读( ...) 评论( ...) 编辑 收藏