我想在程序中实现编号自动生成，在数据中间插入的时候，后面的数据编号自动改变
例如1.1，后面是1.11，1.12，我在中间插入1.11，后面的1.11，1.12自动变成1.12，1.13。
如果1.1后面是1.2，1.3，那就自动变成1.3，1.4。
谁有办法？
原数据：
1
2
2.1
2.1.1
2.2
3
3.1
插入 2
变成
原 现
1 1
插入 2
2 3
2.1 3.1
2.1.1 3.1.1
2.2 3.2
3 4
3.1 4.1
对否？
create
function
dbo.addid(
@addid
varchar
(
30
),
@id
varchar
(
30
))
returns
varchar
(
30
)
as
begin
declare
@newid
varchar
(
30
),
@mid
int
--
@addid = 1.2.1 @id = 1.2.2.1
if
@addid
>=
@id
return
@id
--
[1.2.1 => 1.2.] @addid去尾
if
charindex
(
'
.
'
,
@addid
)
>
0
set
@addid
=
left
(
@addid
,
len
(
@addid
)
+
1
-
charindex
(
'
.
'
,
reverse
(
@addid
)))
--
[1.2.2.1 =>2.1 @newid = 1.2.]@id去头，并将头存入@newid
select
@newid
=
@addid
+
'
.
'
,
@id
=
stuff
(
@id
,
1
,
len
(
@addid
)
+
1
,
''
)
--
@id去中间部分,并存入@mid [2.1=>.1 @mid = 2]
if
charindex
(
'
.
'
,
@id
)
>
1
begin
set
@mid
=
left
(
@id
,
charindex
(
'
.
'
,
@id
)
-
1
)
set
@id
=
stuff
(
@id
,
1
,
charindex
(
'
.
'
,
@id
)
-
1
)
end
else
begin
set
@mid
=
@id
set
@id
=
''
end
--
[@newid = 1.2. + 3 + .1 中间部门加1合并
set
@newid
=
@newid
+
rtrim
(
@mid
+
1
)
+
@id
return
@newid
end
go
--
例子，可以将UPDATE 语句放入表的INSERT 触发器。
declare
@id
varchar
(
30
)
insert
tb(id)
select
@id
update
tb
set
id
=
dbo.addid(
@id
,id)
where
id
>
@id
create
table
tb(id
varchar
(
30
))
insert
tb
select
'
1
'
union
all
select
'
1.1
'
union
all
select
'
2
'
union
all
select
'
2.1
'
union
all
select
'
2.1.2
'
union
all
select
'
2.2
'
union
all
select
'
3
'
union
all
select
'
3.1
'
go
create
function
dbo.addid(
@addid
varchar
(
30
),
@id
varchar
(
30
))
returns
varchar
(
30
)
as
begin
declare
@newid
varchar
(
30
),
@mid
int
--
@addid = 1.2.1 @id = 1.2.2.1
if
@addid
>
@id
return
@id
--
[1.2.1 => 1.2.] @addid去尾
if
charindex
(
'
.
'
,
@addid
)
>
0
set
@addid
=
left
(
@addid
,
len
(
@addid
)
+
1
-
charindex
(
'
.
'
,
reverse
(
@addid
)))
--
[1.2.2.1 =>2.1 @newid = 1.2.]@id去头，并将头存入@newid
--
前缀不同的直接返回
if
@addid
<>
left
(
@id
,
len
(
@addid
))
return
@id
select
@newid
=
@addid
,
@id
=
stuff
(
@id
,
1
,
len
(
@addid
),
''
)
--
@id去中间部分,并存入@mid [2.1=>.1 @mid = 2]
if
charindex
(
'
.
'
,
@id
)
>
1
begin
set
@mid
=
left
(
@id
,
charindex
(
'
.
'
,
@id
)
-
1
)
set
@id
=
stuff
(
@id
,
1
,
charindex
(
'
.
'
,
@id
)
-
1
,
''
)
end
else
begin
set
@mid
=
@id
set
@id
=
''
end
--
[@newid = 1.2. + 3 + .1 中间部门加1合并
set
@newid
=
@newid
+
rtrim
(
@mid
+
1
)
+
@id
return
@newid
end
go
create
trigger
t_tb
on
tb instead
of
insert
as
begin
--
只支持单行插入，如果多行对inserted表使用游标
update
a
set
id
=
dbo.addid(b.id,a.id)
from
tb a,inserted b
where
a.id
>=
b.id
insert
tb
select
*
from
inserted
end
go
select
*
from
tb
order
by
id
/*
id
------------------------------
1
1.1
2
2.1
2.1.2
2.2
3
3.1
*/
insert
tb(id)
select
'
2.1
'
select
*
from
tb
order
by
id
/*
id
------------------------------
1
1.1
2
2.1
2.2
2.2.2
2.3
3
3.1
*/
go
drop
table
tb
drop
function
dbo.addid
create
table
tb(id
varchar
(
30
))
insert
tb
select
'
1
'
union
all
select
'
1.1
'
union
all
select
'
2
'
union
all
select
'
2.1
'
union
all
select
'
2.1.2
'
union
all
select
'
2.2
'
union
all
select
'
3
'
union
all
select
'
3.1
'
go
create
function
dbo.addid(
@addid
varchar
(
30
),
@id
varchar
(
30
))
returns
varchar
(
30
)
as
begin
declare
@newid
varchar
(
30
),
@mid
int
--
@addid = 1.2.1 @id = 1.2.2.1
if
@addid
>
@id
return
@id
--
[1.2.1 => 1.2.] @addid去尾
if
charindex
(
'
.
'
,
@addid
)
>
0
set
@addid
=
left
(
@addid
,
len
(
@addid
)
+
1
-
charindex
(
'
.
'
,
reverse
(
@addid
)))
else
set
@addid
=
''
--
[1.2.2.1 =>2.1 @newid = 1.2.]@id去头，并将头存入@newid
--
前缀不同的直接返回
if
@addid
<>
left
(
@id
,
len
(
@addid
))
return
@id
select
@newid
=
@addid
,
@id
=
stuff
(
@id
,
1
,
len
(
@addid
),
''
)
--
@id去中间部分,并存入@mid [2.1=>.1 @mid = 2]
if
charindex
(
'
.
'
,
@id
)
>
1
begin
set
@mid
=
left
(
@id
,
charindex
(
'
.
'
,
@id
)
-
1
)
set
@id
=
stuff
(
@id
,
1
,
charindex
(
'
.
'
,
@id
)
-
1
,
''
)
end
else
begin
set
@mid
=
@id
set
@id
=
''
end
--
[@newid = 1.2. + 3 + .1 中间部门加1合并
set
@newid
=
@newid
+
rtrim
(
@mid
+
1
)
+
@id
return
@newid
end
go
create
trigger
t_tb
on
tb instead
of
insert
as
begin
--
只支持单行插入，如果多行对inserted表使用游标
update
a
set
id
=
dbo.addid(b.id,a.id)
from
tb a,inserted b
where
a.id
>=
b.id
insert
tb
select
*
from
inserted
end
go
select
*
from
tb
order
by
id
/*
id
------------------------------
1
1.1
2
2.1
2.1.2
2.2
3
3.1
*/
insert
tb(id)
select
'
2.1
'
select
*
from
tb
order
by
id
/*
id
------------------------------
1
1.1
2
2.1
2.2
2.2.2
2.3
3
3.1
*/
insert
tb(id)
select
'
2
'
select
*
from
tb
order
by
id
/*
id
------------------------------
1
1.1
2
3
3.1
3.2
3.2.2
3.3
4
4.1
*/
go
drop
table
tb
drop
function
dbo.addid
我想在程序中实现编号自动生成，在数据中间插入的时候，后面的数据编号自动改变...
转载于:https://www.cnblogs.com/Peter-pan/archive/2008/04/25/1171388.html