LeetCode Contest 186 5392. 分割字符串的最大得分 Maximum Score After Splitting a String

Table of Contents

一、中文版

二、英文版

三、My answer

四、解题报告


一、中文版

给你一个由若干 0 和 1 组成的字符串 s ,请你计算并返回将该字符串分割成两个 非空 子字符串(即  子字符串和  子字符串)所能获得的最大得分。

「分割字符串的得分」为  子字符串中 0 的数量加上  子字符串中 1 的数量。

 

示例 1:

输入:s = "011101"
输出:5 
解释:
将字符串 s 划分为两个非空子字符串的可行方案有:
左子字符串 = "0" 且 右子字符串 = "11101",得分 = 1 + 4 = 5 
左子字符串 = "01" 且 右子字符串 = "1101",得分 = 1 + 3 = 4 
左子字符串 = "011" 且 右子字符串 = "101",得分 = 1 + 2 = 3 
左子字符串 = "0111" 且 右子字符串 = "01",得分 = 1 + 1 = 2 
左子字符串 = "01110" 且 右子字符串 = "1",得分 = 2 + 1 = 3

示例 2:

输入:s = "00111"
输出:5
解释:当 左子字符串 = "00" 且 右子字符串 = "111" 时,我们得到最大得分 = 2 + 3 = 5

示例 3:

输入:s = "1111"
输出:3

提示:

  • 2 <= s.length <= 500
  • 字符串 s 仅由字符 '0' 和 '1' 组成。

二、英文版

Given a string s of zeros and ones, return the maximum score after splitting the string into two non-empty substrings (i.e. left substring and right substring).

The score after splitting a string is the number of zeros in the left substring plus the number of ones in the right substring.

 

Example 1:

Input: s = "011101"
Output: 5 
Explanation: 
All possible ways of splitting s into two non-empty substrings are:
left = "0" and right = "11101", score = 1 + 4 = 5 
left = "01" and right = "1101", score = 1 + 3 = 4 
left = "011" and right = "101", score = 1 + 2 = 3 
left = "0111" and right = "01", score = 1 + 1 = 2 
left = "01110" and right = "1", score = 2 + 1 = 3

Example 2:

Input: s = "00111"
Output: 5
Explanation: When left = "00" and right = "111", we get the maximum score = 2 + 3 = 5

Example 3:

Input: s = "1111"
Output: 3

Constraints:

  • 2 <= s.length <= 500
  • The string s consists of characters '0' and '1' only.

三、My answer

class Solution:
    def maxScore(self, s: str) -> int:
        res = 0
        for i in range(1,len(s)):
            tmp = s[:i].count('0') + s[i:].count('1')
            res = max(res, tmp)
        return res

四、解题报告

因为 s 的长度不会超过 500,所以可以使用暴力遍历方法:

截断每个位置,判断截断前半部分中 0 的个数和截断后半部分中 1 的个数之和。

与 res 比较,选出最大值,赋给 res。

 

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