NYOJ532 不吉利的数字

原题链接

险过代码：

#include 
#define MAX 1000000 + 2
int a[MAX] = {0, 1, 2};

bool Judge(int n){
	while(n){
		if(n % 10) {
			n /= 10;
			continue;
		}
		return false;
	}
	return true;
}

int main(){
	int n, i;
	for(i = 3; i != MAX; ++i)
		if(Judge(i)) a[i] = a[i - 1] + 1;
		else a[i] = a[i - 1];
	while(scanf("%d", &n) == 1)
		if(!Judge(n) || n == 0) printf("Unlucky\n");
		else printf("%d\n", a[n]);
	return 0;
}

由于这题有点类似九进制的意思，所以可以优化成这样：

#include 

bool Judge(int n){
	while(n){
		if(n % 10) {
			n /= 10;
			continue;
		}
		return false;
	}
	return true;
}

int Combine(int n){
	int s = 0, t = 1;
	while(n){
		s += n % 10 * t;
		t *= 9;
		n /= 10;
	}
	return s;
}

int main(){
	int n, i;	
	while(scanf("%d", &n) == 1){
		if(!Judge(n) || !n) printf("Unlucky\n");
		else printf("%d\n", Combine(n));
	}
	return 0;
}

转载于:https://www.cnblogs.com/changmu/p/3639732.html