糖果传递

题目描述

思路

代码

#include 
#include 
#include 

long long n, avg, tot, arr[1000005], ans;
inline long long int read() {
    long long s = 0, f = 1;
    char ch = getchar();
    while (ch < '0' || ch > '9') {
        if (ch == '-') f = -1;
        ch = getchar();
    }
    while (ch >= '0' && ch <= '9') s = s * 10 + ch - '0',
    ch = getchar();
    return s * f;
}
int main() {
    n = read();
    for (int i = 1; i <= n; ++i) {
        arr[i] = read(), tot += arr[i];
    }
    avg = tot / n;
    for (int i = 1; i <= n; ++i) {
        arr[i] -= avg, arr[i] += arr[i - 1];
    }
    std::sort(arr + 1, arr + n + 1);
    for (int i = 1, j = n >> 1; i <= n; ++i) {
        ans += abs(arr[i] - arr[j]);
    }
    printf("%lld\n", ans);
    return 0;
}

转载于:https://www.cnblogs.com/liuzz-20180701/p/11563187.html