A. Winner

time limit per test
1 second
memory limit per test
64 megabytes
input
standard input
output
standard output

The winner of the card game popular in Berland "Berlogging" is determined according to the following rules. If at the end of the game there is only one player with the maximum number of points, he is the winner. The situation becomes more difficult if the number of such players is more than one. During each round a player gains or loses a particular number of points. In the course of the game the number of points is registered in the line "name score", where name is a player's name, and score is the number of points gained in this round, which is an integer number. If score is negative, this means that the player has lost in the round. So, if two or more players have the maximum number of points (say, it equals to m) at the end of the game, than wins the one of them who scored at least m points first. Initially each player has 0 points. It's guaranteed that at the end of the game at least one player has a positive number of points.

Input

The first line contains an integer number n (1  ≤  n  ≤  1000), n is the number of rounds played. Then follow n lines, containing the information about the rounds in "name score" format in chronological order, where name is a string of lower-case Latin letters with the length from 1 to 32, and score is an integer number between -1000 and 1000, inclusive.

Output

Print the name of the winner.

Sample test(s)
input
3
mike 3
andrew 5
mike 2
output
andrew
input
3
andrew 3
andrew 2
mike 5
output
andrew

解题说明:此题的意思是先统计出每个选手的总成绩,然后找到得分最多的选手,考虑到可能存在多个选手得到最高分,那么就以最先得到最高分的选手为获胜者。为了简单,可以用map数组来做,一个map数组是用来统计选手和最终得分情况,找出得分的最大值,另外一个是用来在遍历的时候判断选手有没有达到最高得分,如果达到了就退出,输出答案。


#include
#include
#include
#include
#include
using namespace std;

mapf,g;
string s[1000];
int c[1000],n;
int i,m=0;
int main()
{
    cin>>n;
    for(i=0; i>s[i]>>c[i];
		f[s[i]]+=c[i];
	}
    for(i=0; i


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