mysql8.0 JSON_CONTAINS使用方法

语法：

JSON_CONTAINS(json_doc, val[, path])

案例：

select * from tb
    where info->'$.name' = '特价促销'  or JSON_CONTAINS(info->'$[*].name', '"特价促销"', '$')

 

SET @json = '{"A": 0, "B": {"C": 1}, "D": 2}';

SELECT JSON_CONTAINS(@json, '2', '$.A');
+----------------------------------+
| JSON_CONTAINS(@json, '2', '$.A') |
+----------------------------------+
|                                0 |
+----------------------------------+

SELECT JSON_CONTAINS(@json, '2', '$.D');
+----------------------------------+
| JSON_CONTAINS(@json, '2', '$.D') |
+----------------------------------+
|                                1 |
+----------------------------------+

SELECT JSON_CONTAINS(@json, '{"C": 1}', '$.A');
+-----------------------------------------+
| JSON_CONTAINS(@json, '{"C": 1}', '$.A') |
+-----------------------------------------+
|                                       0 |
+-----------------------------------------+

SELECT JSON_CONTAINS(@json, '{"C": 1}', '$.B');
+-----------------------------------------+
| JSON_CONTAINS(@json, '{"C": 1}', '$.B') |
+-----------------------------------------+
|                                       1 |
+-----------------------------------------+