POJ1002

对于我来说有点难。
在自己的电脑上没问题，但是oj上始终过不了~
不知道为什么为报错

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问题描述###

简单的映射和替换

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难点###

无~

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代码实现###

package poj; import java.util.ArrayList; import java.util.Comparator; import java.util.HashMap; import java.util.Scanner; public class Poj1002 { public static void main(String[] args){ Scanner in =new Scanner(System.in); String s = in.nextLine(); int c = Integer.valueOf(s); HashMap map = new HashMap(); ArrayList list = new ArrayList(); for(int i = 0 ; i < c ; i ++){ String tmp = in.nextLine(); tmp = tmp.replaceAll("-", ""); tmp = tmp.replaceAll("[A-C]", "2"); tmp = tmp.replaceAll("[D-F]", "3"); tmp = tmp.replaceAll("[G-I]", "4"); tmp = tmp.replaceAll("[J-L]", "5"); tmp = tmp.replaceAll("[M-O]", "6"); tmp = tmp.replaceAll("[P,R,S]", "7"); tmp = tmp.replaceAll("[T-V]", "8"); tmp = tmp.replaceAll("[W-Y]", "9"); tmp = tmp.replaceAll("[Q,Z]", ""); Integer count = map.get(tmp); if(count == null){ map.put(tmp, new Integer(1)); list.add(Integer.valueOf(tmp)); } else map.put(tmp, new Integer( count +1)); } in.close(); list.sort(new Comparator() { public int compare(Integer o1, Integer o2) { if(o1.equals(o2)) return 0; else if(o1 < o2) return -1; else return 1; } }); // for(int i = 0 ; i < list.size() ; i ++){ // for(int j = 0 ; j < list.size() -1 ; j ++){ // Integer aV = list.get(j); // Integer bV = list.get(j+1); // if(aV > bV){ // list.set(j, bV); // list.set(j+1, aV); // } // } // } boolean no = true; for(Integer key : list){ String ss = key.toString(); if(map.get(ss) == 1){ continue; } no = false; ss = ss.substring(0, 3)+"-"+ss.substring(3, 7); System.out.println(ss+" "+map.get(key.toString())); } if(no) System.out.println("No duplicates. "); } }
使用ArrayList的sort方法会报compiler error，位置就在sort方法那里
使用自己写的冒泡会报runtime error。
为什么不是超时而是RE呢？不能理解。

2014.08.20 22:00 Update###

找到一个AC的代码，发现其为排序，和题目的降序排列不符，但是居然AC了？？为什么
自己的代码不排序的话，就是WA~
代码如下：
import java.io.BufferedInputStream; import java.io.DataInputStream; import java.io.IOException; import java.util.Map; import java.util.TreeMap; public class Main { @SuppressWarnings("deprecation") public static void main(String[] args) throws IOException { DataInputStream input = new DataInputStream(new BufferedInputStream(System.in)); int number = Integer.parseInt(input.readLine()); Integer count; Map map = new TreeMap(); for (int i = 0; i < number; i++) { String phoneNumber = input.readLine().replace("-", ""); StringBuffer sb = new StringBuffer(); for (int j = 0; j < 7; j++) { char c = phoneNumber.charAt(j); if (Character.isDigit(c)) { sb.append(c); continue; } if (c == 'A' || c == 'B' || c == 'C') { c = '2'; } if (c == 'D' || c == 'E' || c == 'F') { c = '3'; } if (c == 'G' || c == 'H' || c == 'I') { c = '4'; } if (c == 'J' || c == 'K' || c == 'L') { c = '5'; } if (c == 'M' || c == 'N' || c == 'O') { c = '6'; } if (c == 'P' || c == 'R' || c == 'S') { c = '7'; } if (c == 'T' || c == 'U' || c == 'V') { c = '8'; } if (c == 'W' || c == 'X' || c == 'Y') { c = '9'; } sb.append(c); } String result = sb.toString(); if (map.containsKey(result)) { count = map.get(result) + 1; map.put(result, count); } else { map.put(result, 1); } } boolean flag = false; for (String key : map.keySet()) { count = map.get(key); if (count > 1) { flag = true; System.out.println(key.substring(0, 3) + "-" + key.substring(3) + " " + count); } } if (!flag) { System.out.println("No duplicates. "); } } }