PAT乙级1082

题目链接

实现

#include 
#include 
#include 
using namespace std;

int main()
{
	int N, ID,x, y, maxName, minName;
	double dis,max=0,min=20000;
	scanf("%d", &N);
	while (N--)
	{
		scanf("%d %d %d", &ID, &x, &y);
		dis = sqrt(pow(x, 2)+ pow(y, 2));
		if (dis > max)
			maxName = ID; max = dis;
		if (dis < min)
			minName = ID; min = dis;
	}
	printf("%04d %04d", minName, maxName);
    return 0;
}