sql查询50题

/*
一个项目涉及到的50个Sql语句
问题及描述:
--1.学生表
Student(S#,Sname,Sage,Ssex) --S# 学生编号,Sname 学生姓名,Sage 出生年月,Ssex 学生性别
--2.课程表 
Course(C#,Cname,T#) --C# --课程编号,Cname 课程名称,T# 教师编号
--3.教师表 
Teacher(T#,Tname) --T# 教师编号,Tname 教师姓名
--4.成绩表 
SC(S#,C#,score) --S# 学生编号,C# 课程编号,score 分数
select * from Student
select * from Course
select * from Teacher
select * from SC
*/
--创建测试数据
create table Student(S# varchar(10),Sname nvarchar(10),Sage datetime,Ssex nvarchar(10))
insert into Student values('01' , N'赵雷' , '1990-01-01' , N'男')
insert into Student values('02' , N'钱电' , '1990-12-21' , N'男')
insert into Student values('03' , N'孙风' , '1990-05-20' , N'男')
insert into Student values('04' , N'李云' , '1990-08-06' , N'男')
insert into Student values('05' , N'周梅' , '1991-12-01' , N'女')
insert into Student values('06' , N'吴兰' , '1992-03-01' , N'女')
insert into Student values('07' , N'郑竹' , '1989-07-01' , N'女')
insert into Student values('08' , N'王菊' , '1990-01-20' , N'女')
create table Course(C# varchar(10),Cname nvarchar(10),T# varchar(10))
insert into Course values('01' , N'语文' , '02')
insert into Course values('02' , N'数学' , '01')
insert into Course values('03' , N'英语' , '03')
create table Teacher(T# varchar(10),Tname nvarchar(10))
insert into Teacher values('01' , N'张三')
insert into Teacher values('02' , N'李四')
insert into Teacher values('03' , N'王五')
create table SC(S# varchar(10),C# varchar(10),score decimal(18,1))
insert into SC values('01' , '01' , 80)
insert into SC values('01' , '02' , 90)
insert into SC values('01' , '03' , 99)
insert into SC values('02' , '01' , 70)
insert into SC values('02' , '02' , 60)
insert into SC values('02' , '03' , 80)
insert into SC values('03' , '01' , 80)
insert into SC values('03' , '02' , 80)
insert into SC values('03' , '03' , 80)
insert into SC values('04' , '01' , 50)
insert into SC values('04' , '02' , 30)
insert into SC values('04' , '03' , 20)
insert into SC values('05' , '01' , 76)
insert into SC values('05' , '02' , 87)
insert into SC values('06' , '01' , 31)
insert into SC values('06' , '03' , 34)
insert into SC values('07' , '02' , 89)
insert into SC values('07' , '03' , 98)
go
--1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数
--1.1、查询同时存在"01"课程和"02"课程的情况
--1.2、查询同时存在"01"课程和"02"课程的情况和存在"01"课程但可能不存在"02"课程的情况(不存在时显示为null)(以下存在相同内容时不再解释)
--2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数
--2.1、查询同时存在"01"课程和"02"课程的情况
--2.2、查询同时存在"01"课程和"02"课程的情况和不存在"01"课程但存在"02"课程的情况
--3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩
--4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩
--4.1、查询在sc表存在成绩的学生信息的SQL语句。
--4.2、查询在sc表中不存在成绩的学生信息的SQL语句。
--5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩
--5.1、查询所有有成绩的SQL。
--5.2、查询所有(包括有成绩和无成绩)的SQL。
--6、查询"李"姓老师的数量 
--7、查询学过"张三"老师授课的同学的信息 
--8、查询没学过"张三"老师授课的同学的信息 
--9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息
--10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息
--11、查询没有学全所有课程的同学的信息 
--12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息 
--13、查询和"01"号的同学学习的课程完全相同的其他同学的信息 
--14、查询没学过"张三"老师讲授的任一门课程的学生姓名 
--15、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩 
--16、检索"01"课程分数小于60,按分数降序排列的学生信息
--17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
--17.1 SQL 2000 静态 
--17.2 SQL 2000 动态 
--17.3 有关sql 2005的动静态写法参见我的文章《普通行列转换(version 2.0)》或《普通行列转换(version 3.0)》。
--18、查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率
--及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90
--19、按各科成绩进行排序,并显示排名
--19.1 sql 2000用子查询完成
--Score重复时保留名次空缺
--Score重复时合并名次
--19.2 sql 2005用rank,DENSE_RANK完成
--Score重复时保留名次空缺(rank完成)
--Score重复时合并名次(DENSE_RANK完成)
--20、查询学生的总成绩并进行排名
--20.1 查询学生的总成绩
--20.2 查询学生的总成绩并进行排名,sql 2000用子查询完成,分总分重复时保留名次空缺和不保留名次空缺两种。
--20.3 查询学生的总成绩并进行排名,sql 2005用rank,DENSE_RANK完成,分总分重复时保留名次空缺和不保留名次空缺两种。
--21、查询不同老师所教不同课程平均分从高到低显示 
--22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩
--22.1 sql 2000用子查询完成
--Score重复时保留名次空缺
--Score重复时合并名次
--22.2 sql 2005用rank,DENSE_RANK完成
--Score重复时保留名次空缺(rank完成)
--Score重复时合并名次(DENSE_RANK完成)
--23、统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比 
--23.1 统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]
--23.2 统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[<60]及所占百分比 
--24、查询学生平均成绩及其名次 
--24.1 查询学生的平均成绩并进行排名,sql 2000用子查询完成,分平均成绩重复时保留名次空缺和不保留名次空缺两种。
--24.2 查询学生的平均成绩并进行排名,sql 2005用rank,DENSE_RANK完成,分平均成绩重复时保留名次空缺和不保留名次空缺两种。
--25、查询各科成绩前三名的记录
--25.1 分数重复时保留名次空缺
--25.2 分数重复时不保留名次空缺,合并名次
--sql 2000用子查询实现
--sql 2005用DENSE_RANK实现
--26、查询每门课程被选修的学生数 
--27、查询出只有两门课程的全部学生的学号和姓名 
--28、查询男生、女生人数 
--29、查询名字中含有"风"字的学生信息
--30、查询同名同性学生名单,并统计同名人数 
--31、查询1990年出生的学生名单(注:Student表中Sage列的类型是datetime) 
--32、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列 
--33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩 
--34、查询课程名称为"数学",且分数低于60的学生姓名和分数 
--35、查询所有学生的课程及分数情况; 
--36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数; 
--37、查询不及格的课程
--38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名; 
--39、求每门课程的学生人数 
--40、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩
--40.1 当最高分只有一个时
--40.2 当最高分出现多个时
--41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩 
--42、查询每门功成绩最好的前两名 
--43、统计每门课程的学生选修人数(超过5人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列  
--44、检索至少选修两门课程的学生学号 
--45、查询选修了全部课程的学生信息 
--46、查询各学生的年龄
--46.1 只按照年份来算
--46.2 按照出生日期来算,当前月日 < 出生年月的月日则,年龄减一
--47、查询本周过生日的学生
--48、查询下周过生日的学生
--49、查询本月过生日的学生

--50、查询下月过生日的学生 

 

Student(Sid,Sname,Sage,Ssex) 学生表

Course(Cid,Cname,Tid) 课程表
SC(Sid,Cid,score) 成绩表
Teacher(Tid,Tname) 教师表
 
练习内容:
1.查询“某1”课程比“某2”课程成绩高的所有学生的学号;
SELECT a.sid FROM (SELECT sid,score FROM SC WHERE cid=1) a,(SELECT sid,score FROM SC WHERE cid=3) b WHERE a.score>b.score AND a.sid=b.sid;
此题知识点,嵌套查询和给查出来的表起别名
2.查询平均成绩大于60分的同学的学号和平均成绩;
SELECT sid,avg(score)  FROM sc  GROUP BY sid having avg(score) >60;
此题知识点,GROUP BY 语句用于结合合计函数,根据一个或多个列对结果集进行分组。group by后面不能接where,having代替了where
3.查询所有同学的学号、姓名、选课数、总成绩
SELECT Student.sid,Student.Sname,count(SC.cid),sum(score)FROM Student left Outer JOIN SC on Student.sid=SC.cid GROUP BY Student.sid,Sname
4.查询姓“李”的老师的个数;
select count(teacher.tid)from teacher where teacher.tname like'李%'
5.查询没学过“叶平”老师课的同学的学号、姓名;
SELECT Student.sid,Student.Sname FROM Student WHERE sid not in (SELECT distinct( SC.sid) FROM SC,Course,Teacher WHERE  SC.cid=Course.cid AND Teacher.id=Course.tid AND Teacher.Tname='叶平');
 此题知识点,distinct是去重的作用
6.查询学过“```”并且也学过编号“```”课程的同学的学号、姓名;
select a.SID,a.SNAME from (select student.SNAME,student.SID from student,course,sc where cname='c++'and sc.sid=student.sid and sc.cid=course.cid) a,
(select student.SNAME,student.SID from student,course,sc where cname='english'and sc.sid=student.sid and sc.cid=course.cid) b where a.sid=b.sid;
标准答案(但是好像不好使)SELECT Student.S#,Student.Sname FROM Student,SC WHERE Student.S#=SC.S# AND SC.C#='001'and exists( SELECT * FROM SC as SC_2 WHERE SC_2.S#=SC.S# AND SC_2.C#='002');  
此题知识点,exists是在集合里找数据,as就是起别名
7.查询学过“叶平”老师所教的所有课的同学的学号、姓名;
select a.sid,a.sname from (select student.sid,student.sname from student,teacher,course,sc 
where teacher.TNAME='杨巍巍' and teacher.tid=course.tid and course.cid=sc.cid and student.sid=sc.sid) a
标准答案:SELECT sid,Sname FROM Student WHERE sid in (SELECT sid FROM SC ,Course ,Teacher WHERE SC.cid=Course.cid AND Teacher.tid=Course.tid AND Teacher.Tname='杨巍巍' GROUP BY sid having count(SC.cid)=(SELECT count(cid) FROM Course,Teacher  WHERE Teacher.tid=Course.tid AND Tname='杨巍巍'))
8.查询课程编号“”的成绩比课程编号“”课程低的所有同学的学号、姓名;
select a.sid,a.sname from(select student.SID,student.sname,sc.SCORE  from student,sc where student.sid=sc.sid and sc.cid=1) a,
(select student.SID,student.sname,sc.score from student,sc where student.sid=sc.sid and sc.cid=2) b where a.score
标准答案:SELECT sid,Sname FROM (SELECT Student.sid,Student.Sname,score ,
(SELECT score FROM SC SC_2 WHERE SC_2.sid=Student.sid AND SC_2.cid=1) score2 FROM Student,SC
WHERE Student.sid=SC.sid AND cid=1) S_2 WHERE score2
9.查询所有课程成绩小于分的同学的学号、姓名;
SELECT sid,Sname FROM Student WHERE sid not in (SELECT Student.sid FROM Student,SC WHERE Student.sid=SC.sid AND score>60); 
此题知识点,先查出大于60分的,然后not in 就是小于60分的了
10.查询没有学全所有课的同学的学号、姓名;
SELECT Student.sid,Student.Sname  FROM Student,SC  
WHERE Student.sid=SC.sid GROUP BY  Student.sid,Student.Sname having count(cid) <(SELECT count(cid) FROM Course); 
11.查询至少有一门课与学号为“”的同学所学相同的同学的学号和姓名;
12.查询至少学过学号为“”同学所有一门课的其他同学学号和姓名;
SELECT student.sid,student.Sname FROM Student,SC WHERE Student.sid=SC.sid AND cid in (SELECT cid FROM SC WHERE sid=1)
此题知识点,SELECT sid,Sname FROM Student,SC WHERE Student.sid=SC.sid AND cid in (SELECT cid FROM SC WHERE sid=1)这样写是错误的,因为from后面是两个表,不能明确是哪个表里面的sid和sname所以错误提示是“未明确定义列”
13.把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩;
update sc set score=(select avg(score) from sc,course,teacher where course.cid=sc.cid and course.tid=teacher.tid and teacher.tname='杨巍巍')
14.查询和“”号的同学学习的课程完全相同的其他同学学号和姓名;
SELECT sid FROM SC WHERE cid in (SELECT cid FROM SC WHERE sid=6) GROUP BY sid having count(*)=(SELECT count(*) FROM SC WHERE sid=6); 
此题知识点,用数量来判断 
15.删除学习“叶平”老师课的SC表记录; 
delete from sc s where s.cid in (select c.cid from teacher t,course c where t.tid = c.tid and tname='李子')
此题知识点,嵌套查询可以分布考虑,先查出李子老师都交了什么课的id,然后再删除那些id的值
16.向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“”课程的同学学号、课程的平均成绩;
Insert into SC SELECT sid,2,(SELECT avg(score) FROM SC WHERE cid=2) FROM Student WHERE sid not in (SELECT sid FROM SC WHERE cid=2); 
17.按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示:学生ID,,数据库,企业管理,英语,有效课程数,有效平均分;(没做出来)
18.查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分;
select cid as 课程号,max(score)as 最高分,min(score) as 最低分 from sc group by cid
标准答案(但是运行不好使)SELECT L.cid As 课程ID,L.score AS 最高分,R.score AS 最低分 
FROM SC L ,SC AS R  
WHERE L.cid = R.cid AND  
L.score = (SELECT MAX(IL.score)  
FROM SC AS IL,Student AS IM  
WHERE L.cid = IL.cid AND IM.sid=IL.sid  
GROUP BY IL.cid)  
AND  R.Score = (SELECT MIN(IR.score) FROM SC AS IR WHERE R.cid = IR.cid  GROUP BY IR.cid ); 
19.按各科平均成绩从低到高和及格率的百分数从高到低顺序
26.查询每门课程被选修的学生数
select sc.cid,count(sc.sid) from sc,course where sc.cid=course.cid group by sc.cid
27.查询出只选修了一门课程的全部学生的学号和姓名
SELECT SC.sid,Student.Sname,count(cid) AS 选课数 FROM SC ,Student  
WHERE SC.sid=Student.sid GROUP BY SC.sid ,Student.Sname having count(cid)=1;
32.查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列
SELECT Cid,Avg(score) FROM SC GROUP BY cid ORDER BY Avg(score),cid DESC ;
37.查询不及格的课程,并按课程号从大到小排列 
SELECT cid,sid FROM sc WHERE score <60 ORDER BY cid 
38.查询课程编号为且课程成绩在分以上的学生的学号和姓名;
select student.sid,student.sname from sc,student where sc.cid=1 and sc.score>60 and sc.sid=student.sid
39、求选了课程的学生人数 
    select count(*) from sc; 
40.查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩
select student.sname,sc.score from sc,student,teacher,course c where teacher.tname='李子'
and teacher.tid=c.tid and c.cid=sc.cid and sc.sid=student.sid and sc.score=(select max(score)from sc where sc.cid=c.cid)
41.查询各个课程及相应的选修人数
select sc.cid ,count(sc.sid)from sc,student where sc.sid=student.sid group by sc.cid 
42、查询不同课程成绩相同的学生的学号、课程号、学生成绩 
select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ; 
43.查询每门功成绩最好的前两名
 SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数 
      FROM SC t1 
      WHERE score IN (SELECT TOP 2 score 
              FROM SC 
              WHERE t1.C#= C# 
            ORDER BY score DESC 
              ) 
      ORDER BY t1.C#; 
44.统计每门课程的学生选修人数(超过人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列
select sc.cid,count(sc.cid)from sc,course where sc.cid=course.cid group by sc.cid  order by sc.cid desc
45.检索至少选修两门课程的学生学号
SELECT sid FROM  sc group  by  sid having  count(*)  >  =  2  
 
rownum的用法
查询所有成绩第二名到第四名的成绩
select * from (select rownum p,t.score from(SELECT s.score score FROM sc s ORDER BY score desc)t )tt where tt.p>1 and tt.p<5
 45、检索至少选修两门课程的学生学号 
    select S# 
    from sc 
    group by s# 
    having count(*) > = 2 
46、查询全部学生都选修的课程的课程号和课程名 
    select C#,Cname 
    from Course 
    where C# in (select c# from sc group by c#) 
47、查询没学过“叶平”老师讲授的任一门课程的学生姓名 
    select Sname from Student where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='叶平'); 
48、查询两门以上不及格课程的同学的学号及其平均成绩 
    select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score <60 group by S# having count(*)>2)group by S#; 
49、检索“004”课程分数小于60,按分数降序排列的同学学号 
    select S# from SC where C#='004'and score <60 order by score desc; 
50、删除“002”同学的“001”课程的成绩 
delete from Sc where S#='001'and C#='001';
 

Student(S#,Sname,Sage,Ssex) 学生表 
Course(C#,Cname,T#) 课程表 
SC(S#,C#,score) 成绩表 
Teacher(T#,Tname) 教师表

 

问题: 
1、查询“001”课程比“002”课程成绩高的所有学生的学号; 
select a.S# from (select s#,score from SC where C#='001') a,(select s#,score 
from SC where C#='002') b 
where a.score>b.score and a.s#=b.s#; 
2、查询平均成绩大于60分的同学的学号和平均成绩; 
    select S#,avg(score) 
    from sc 
    group by S# having avg(score) >60; 
3、查询所有同学的学号、姓名、选课数、总成绩; 
select Student.S#,Student.Sname,count(SC.C#),sum(score) 
from Student left Outer join SC on Student.S#=SC.S# 
group by Student.S#,Sname 
4、查询姓“李”的老师的个数; 
select count(distinct(Tname)) 
from Teacher 
where Tname like '李%'; 
5、查询没学过“叶平”老师课的同学的学号、姓名; 
    select Student.S#,Student.Sname 
    from Student 
    where S# not in (select distinct( SC.S#) from SC,Course,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平'); 
6、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名; 
select Student.S#,Student.Sname from Student,SC where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 where SC_2.S#=SC.S# and SC_2.C#='002'); 
7、查询学过“叶平”老师所教的所有课的同学的学号、姓名; 
select S#,Sname 
from Student 
where S# in (select S# from SC ,Course ,Teacher where SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平' group by S# having count(SC.C#)=(select count(C#) from Course,Teacher where Teacher.T#=Course.T# and Tname='叶平')); 
8、查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名; 
Select S#,Sname from (select Student.S#,Student.Sname,score ,(select score from SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') score2 
from Student,SC where Student.S#=SC.S# and C#='001') S_2 where score2 9、查询所有课程成绩小于60分的同学的学号、姓名; 
select S#,Sname 
from Student 
where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and score>60); 
10、查询没有学全所有课的同学的学号、姓名; 
    select Student.S#,Student.Sname 
    from Student,SC 
    where Student.S#=SC.S# group by Student.S#,Student.Sname having count(C#) <(select count(C#) from Course);

11、查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名; 
    select S#,Sname from Student,SC where Student.S#=SC.S# and C# in select C# from SC where S#='1001'; 
12、查询至少学过学号为“001”同学所有一门课的其他同学学号和姓名; 
    select distinct SC.S#,Sname 
    from Student,SC 
    where Student.S#=SC.S# and C# in (select C# from SC where S#='001'); 
13、把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩; 
    update SC set score=(select avg(SC_2.score) 
    from SC SC_2 
    where SC_2.C#=SC.C# ) from Course,Teacher where Course.C#=SC.C# and Course.T#=Teacher.T# and Teacher.Tname='叶平'); 
14、查询和“1002”号的同学学习的课程完全相同的其他同学学号和姓名; 
    select S# from SC where C# in (select C# from SC where S#='1002') 
    group by S# having count(*)=(select count(*) from SC where S#='1002'); 
15、删除学习“叶平”老师课的SC表记录; 
    Delect SC 
    from course ,Teacher 
    where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='叶平'; 
16、向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“003”课程的同学学号、2、 
    号课的平均成绩; 
    Insert SC select S#,'002',(Select avg(score) 
    from SC where C#='002') from Student where S# not in (Select S# from SC where C#='002'); 
17、按平均成绩从高到低显示所有学生的“数据库”、“企业管理”、“英语”三门的课程成绩,按如下形式显示: 学生ID,,数据库,企业管理,英语,有效课程数,有效平均分 
    SELECT S# as 学生ID 
        ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='004') AS 数据库 
        ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='001') AS 企业管理 
        ,(SELECT score FROM SC WHERE SC.S#=t.S# AND C#='006') AS 英语 
        ,COUNT(*) AS 有效课程数, AVG(t.score) AS 平均成绩 
    FROM SC AS t 
    GROUP BY S# 
    ORDER BY avg(t.score) 
18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分 
    SELECT L.C# As 课程ID,L.score AS 最高分,R.score AS 最低分 
    FROM SC L ,SC AS R 
    WHERE L.C# = R.C# and 
        L.score = (SELECT MAX(IL.score) 
                      FROM SC AS IL,Student AS IM 
                      WHERE L.C# = IL.C# and IM.S#=IL.S# 
                      GROUP BY IL.C#) 
        AND 
        R.Score = (SELECT MIN(IR.score) 
                      FROM SC AS IR 
                      WHERE R.C# = IR.C# 
                  GROUP BY IR.C# 
                    ); 
19、按各科平均成绩从低到高和及格率的百分数从高到低顺序 
    SELECT t.C# AS 课程号,max(course.Cname)AS 课程名,isnull(AVG(score),0) AS 平均成绩 
        ,100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分数 
    FROM SC T,Course 
    where t.C#=course.C# 
    GROUP BY t.C# 
    ORDER BY 100 * SUM(CASE WHEN isnull(score,0)>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC 
20、查询如下课程平均成绩和及格率的百分数(用"1行"显示): 企业管理(001),马克思(002),OO&UML (003),数据库(004) 
    SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 企业管理平均分 
        ,100 * SUM(CASE WHEN C# = '001' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' THEN 1 ELSE 0 END) AS 企业管理及格百分数 
        ,SUM(CASE WHEN C# = '002' THEN score ELSE 0 END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 马克思平均分 
        ,100 * SUM(CASE WHEN C# = '002' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' THEN 1 ELSE 0 END) AS 马克思及格百分数 
        ,SUM(CASE WHEN C# = '003' THEN score ELSE 0 END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS UML平均分 
        ,100 * SUM(CASE WHEN C# = '003' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' THEN 1 ELSE 0 END) AS UML及格百分数 
        ,SUM(CASE WHEN C# = '004' THEN score ELSE 0 END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 数据库平均分 
        ,100 * SUM(CASE WHEN C# = '004' AND score >= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' THEN 1 ELSE 0 END) AS 数据库及格百分数 
FROM SC


21、查询不同老师所教不同课程平均分从高到低显示 
SELECT max(Z.T#) AS 教师ID,MAX(Z.Tname) AS 教师姓名,C.C# AS 课程ID,MAX(C.Cname) AS 课程名称,AVG(Score) AS 平均成绩 
    FROM SC AS T,Course AS C ,Teacher AS Z 
    where T.C#=C.C# and C.T#=Z.T# 
GROUP BY C.C# 
ORDER BY AVG(Score) DESC 
22、查询如下课程成绩第 3 名到第 6 名的学生成绩单:企业管理(001),马克思(002),UML (003),数据库(004) 
    [学生ID],[学生姓名],企业管理,马克思,UML,数据库,平均成绩 
    SELECT DISTINCT top 3 
      SC.S# As 学生学号, 
        Student.Sname AS 学生姓名 , 
      T1.score AS 企业管理, 
      T2.score AS 马克思, 
      T3.score AS UML, 
      T4.score AS 数据库, 
      ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) as 总分 
      FROM Student,SC LEFT JOIN SC AS T1 
                      ON SC.S# = T1.S# AND T1.C# = '001' 
            LEFT JOIN SC AS T2 
                      ON SC.S# = T2.S# AND T2.C# = '002' 
            LEFT JOIN SC AS T3 
                      ON SC.S# = T3.S# AND T3.C# = '003' 
            LEFT JOIN SC AS T4 
                      ON SC.S# = T4.S# AND T4.C# = '004' 
      WHERE student.S#=SC.S# and 
      ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) 
      NOT IN 
      (SELECT 
            DISTINCT 
            TOP 15 WITH TIES 
            ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) 
      FROM sc 
            LEFT JOIN sc AS T1 
                      ON sc.S# = T1.S# AND T1.C# = 'k1' 
            LEFT JOIN sc AS T2 
                      ON sc.S# = T2.S# AND T2.C# = 'k2' 
            LEFT JOIN sc AS T3 
                      ON sc.S# = T3.S# AND T3.C# = 'k3' 
            LEFT JOIN sc AS T4 
                      ON sc.S# = T4.S# AND T4.C# = 'k4' 
      ORDER BY ISNULL(T1.score,0) + ISNULL(T2.score,0) + ISNULL(T3.score,0) + ISNULL(T4.score,0) DESC);

23、统计列印各科成绩,各分数段人数:课程ID,课程名称,[100-85],[85-70],[70-60],[ <60] 
    SELECT SC.C# as 课程ID, Cname as 课程名称 
        ,SUM(CASE WHEN score BETWEEN 85 AND 100 THEN 1 ELSE 0 END) AS [100 - 85] 
        ,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 1 ELSE 0 END) AS [85 - 70] 
        ,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 1 ELSE 0 END) AS [70 - 60] 
        ,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) AS [60 -] 
    FROM SC,Course 
    where SC.C#=Course.C# 
    GROUP BY SC.C#,Cname;

24、查询学生平均成绩及其名次 
      SELECT 1+(SELECT COUNT( distinct 平均成绩) 
              FROM (SELECT S#,AVG(score) AS 平均成绩 
                      FROM SC 
                  GROUP BY S# 
                  ) AS T1 
            WHERE 平均成绩 > T2.平均成绩) as 名次, 
      S# as 学生学号,平均成绩 
    FROM (SELECT S#,AVG(score) 平均成绩 
            FROM SC 
        GROUP BY S# 
        ) AS T2 
    ORDER BY 平均成绩 desc; 

25、查询各科成绩前三名的记录:(不考虑成绩并列情况) 
      SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数 
      FROM SC t1 
      WHERE score IN (SELECT TOP 3 score 
              FROM SC 
              WHERE t1.C#= C# 
            ORDER BY score DESC 
              ) 
      ORDER BY t1.C#; 
26、查询每门课程被选修的学生数 
select c#,count(S#) from sc group by C#; 
27、查询出只选修了一门课程的全部学生的学号和姓名 
select SC.S#,Student.Sname,count(C#) AS 选课数 
from SC ,Student 
where SC.S#=Student.S# group by SC.S# ,Student.Sname having count(C#)=1; 
28、查询男生、女生人数 
    Select count(Ssex) as 男生人数 from Student group by Ssex having Ssex='男'; 
    Select count(Ssex) as 女生人数 from Student group by Ssex having Ssex='女'; 
29、查询姓“张”的学生名单 
    SELECT Sname FROM Student WHERE Sname like '张%'; 
30、查询同名同性学生名单,并统计同名人数 
select Sname,count(*) from Student group by Sname having count(*)>1;; 
31、1981年出生的学生名单(注:Student表中Sage列的类型是datetime) 
    select Sname, CONVERT(char (11),DATEPART(year,Sage)) as age 
    from student 
    where CONVERT(char(11),DATEPART(year,Sage))='1981'; 
32、查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列 
    Select C#,Avg(score) from SC group by C# order by Avg(score),C# DESC ; 
33、查询平均成绩大于85的所有学生的学号、姓名和平均成绩 
    select Sname,SC.S# ,avg(score) 
    from Student,SC 
    where Student.S#=SC.S# group by SC.S#,Sname having    avg(score)>85; 
34、查询课程名称为“数据库”,且分数低于60的学生姓名和分数 
    Select Sname,isnull(score,0) 
    from Student,SC,Course 
    where SC.S#=Student.S# and SC.C#=Course.C# and Course.Cname='数据库'and score <60; 
35、查询所有学生的选课情况; 
    SELECT SC.S#,SC.C#,Sname,Cname 
    FROM SC,Student,Course 
    where SC.S#=Student.S# and SC.C#=Course.C# ; 
36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数; 
    SELECT distinct student.S#,student.Sname,SC.C#,SC.score 
    FROM student,Sc 
    WHERE SC.score>=70 AND SC.S#=student.S#; 
37、查询不及格的课程,并按课程号从大到小排列 
    select c# from sc where scor e <60 order by C# ; 
38、查询课程编号为003且课程成绩在80分以上的学生的学号和姓名; 
    select SC.S#,Student.Sname from SC,Student where SC.S#=Student.S# and Score>80 and C#='003'; 
39、求选了课程的学生人数 
    select count(*) from sc; 
40、查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩 
    select Student.Sname,score 
    from Student,SC,Course C,Teacher 
    where Student.S#=SC.S# and SC.C#=C.C# and C.T#=Teacher.T# and Teacher.Tname='叶平' and SC.score=(select max(score)from SC where C#=C.C# ); 
41、查询各个课程及相应的选修人数 
    select count(*) from sc group by C#; 
42、查询不同课程成绩相同的学生的学号、课程号、学生成绩 
select distinct A.S#,B.score from SC A ,SC B where A.Score=B.Score and A.C# <>B.C# ; 
43、查询每门功成绩最好的前两名 
    SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数 
      FROM SC t1 
      WHERE score IN (SELECT TOP 2 score 
              FROM SC 
              WHERE t1.C#= C# 
            ORDER BY score DESC 
              ) 
      ORDER BY t1.C#; 
44、统计每门课程的学生选修人数(超过10人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列 
    select C# as 课程号,count(*) as 人数 
    from sc 
    group by C# 
    order by count(*) desc,c# 
45、检索至少选修两门课程的学生学号 
    select S# 
    from sc 
    group by s# 
    having count(*) > = 2 
46、查询全部学生都选修的课程的课程号和课程名 
    select C#,Cname 
    from Course 
    where C# in (select c# from sc group by c#) 
47、查询没学过“叶平”老师讲授的任一门课程的学生姓名 
    select Sname from Student where S# not in (select S# from Course,Teacher,SC where Course.T#=Teacher.T# and SC.C#=course.C# and Tname='叶平'); 
48、查询两门以上不及格课程的同学的学号及其平均成绩 
    select S#,avg(isnull(score,0)) from SC where S# in (select S# from SC where score <60 group by S# having count(*)>2)group by S#; 
49、检索“004”课程分数小于60,按分数降序排列的同学学号 
    select S# from SC where C#='004'and score <60 order by score desc; 
50、删除“002”同学的“001”课程的成绩 
delete from Sc where S#='001'and C#='001';

转载于:https://www.cnblogs.com/haohaoyuan/p/9124595.html

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