python将字符串转为矩阵

将字符串转换为矩阵,分为四步:

1.将字符串切分为一个list

d = "2 3 4 5 6 8 1 2 "

dlist = d.strip(' ').split(' ')

2.将list中的str转换为int

dint = map(int, dlist) 

3.将list转换为array

darr =  np.array(dint)

4.将array数组转换为矩阵,这里转为一个三维矩阵

daresh = darr.reshape(2,2,2)

import numpy as np

d = "2 3 4 5 6 8 1 2 "
dlist = d.strip(' ').split(' ')  #转换成一个list
print dlist    # ['2', '3', '4', '5', '6', '8', '1', '2']

dint = map(int, dlist)    # 将list中str转换为int
print dint    # [2, 3, 4, 5, 6, 8, 1, 2]

darr =  np.array(dint)    # 将list转换为array
print(darr)    # [2 3 4 5 6 8 1 2]

# da = darr[0:-1]    # 得到array数组的前len(darr)-1个
# print da    # [2 3 4 5 6 8 1]

daresh = darr.reshape(2,2,2)    # 将array转换为3维(2,2,2)的矩阵
print daresh
'''
[[[2 3]
  [4 5]]

 [[6 8]
  [1 2]]]
'''



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