sort函数是list列表中的函数,而sorted可以对list或者iterator进行排序
>>> a = [1,2,1,4]
>>> a.sort()
>>> a
[1, 1, 2, 4]
>>> a = [1,2,1,4]
>>> sorted(a)
[1, 1, 2, 4]
>>> a
[1, 2, 1, 4]
各个参数说明:
iterable可以是list或者iterator;
cmp是带两个参数的比较函数;
key 是带一个参数的函数;
reverse为False或者True,表示是否反转;
>>> list1 = [('david', 90), ('mary',90), ('sara',80),('lily',95)]
# 首字母排序
>>> sorted(list1,cmp = lambda x,y: cmp(x[0],y[0]))
[('david', 90), ('lily', 95), ('mary', 90), ('sara', 80)]
# 得分排序
>>> sorted(list1,cmp = lambda x,y: cmp(x[1],y[1]))
[('sara', 80), ('david', 90), ('mary', 90), ('lily', 95)]
>>> list1 = [('david', 90), ('mary',90), ('sara',80),('lily',95)]
# 首字母排序
>>> sorted(list1,key = lambda list1: list1[0])
[('david', 90), ('lily', 95), ('mary', 90), ('sara', 80)]
# 得分排序
>>> sorted(list1,key = lambda list1: list1[1])
[('sara', 80), ('david', 90), ('mary', 90), ('lily', 95)]
>>> sorted(list1,reverse = True)
# 首字母反转排序
[('sara', 80), ('mary', 90), ('lily', 95), ('david', 90)]
>>> from operator import itemgetter
# 得分排序
>>> sorted(list1, key=itemgetter(1))
[('sara', 80), ('david', 90), ('mary', 90), ('lily', 95)]
# 首字母排序
>>> sorted(list1, key=itemgetter(0))
[('david', 90), ('lily', 95), ('mary', 90), ('sara', 80)]
import operator
a = [1, 2, 3, 4, 5, 6]
b = operator.itemgetter(5)
c = b(a)
print(c)
结果为:6
总结:
operator.itemgetter()函数获取的不是值,而是定义了一个函数,通过这个函数可以获取到对应的值
>>> sorted(list1, key=itemgetter(0,1))
[('david', 90), ('lily', 95), ('mary', 90), ('sara', 80)]