D. Alice, Bob and Candies

Alice, Bob and Candies

  • 题目链接:https://codeforces.com/contest/1352/problem/D

题意:Alice是从左边开始吃,而Bob从右边开始吃,两个人轮流吃,Alice先开始,下一次吃的人要比上一次吃的人多,最后求出两个人每个人吃了多少颗糖果,以及轮流了多少次;

涉及知识点:

  • 简单模拟

solution:

  • 做 法 较 多 做法较多

std:


#include 
using namespace std;

int n,t;
const int N = 1010;
int a[N];
int Left,Right,ans;
int main()
{
    cin >> t;
    while(t --)
    {
        cin >> n;
        for(int i = 1;i <= n;i ++)cin >> a[i];
        Left = 0,Right = 0,ans = 0;
        int i = 1,j = n,aim = 0;
        while(1)
        {
            int res = 0;
            int k;
            for(k = i;k <= j;k ++){
                res += a[k];
                if(res > aim){

                    break;
                }
            }
            if(!res)break;
            if(res > aim){
                aim = res;
                Left += res;
                i = k + 1;
                ans++;
            }
            else{
                Left += res;
                ans++;
                break;
            }
            res = 0;
            for(k = j;k >= i;k --){
                res += a[k];
                if(res > aim){
                    break;
                }
            }
            if(!res)break;
            if(res > aim){
                aim = res;
                Right += res;
                j = k - 1;
                ans++;
            }
            else{
                Right += res;
                ans++;
                break;
            }
        }
        cout << ans << " " << Left << " " << Right << endl;
    }
    
    return 0;
}

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