A + B Problem II （大数加模拟，，坑点在格式错误）

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B. 

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000. 

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases. 

Sample Input

2
1 2
112233445566778899 998877665544332211

Sample Output

Case 1:
1 + 2 = 3

Case 2:
112233445566778899 + 998877665544332211 = 1111111111111111110

格式错误的坑就是在最后一个没有  回车

还要注意初始化！！！！

#include
#include
#include
using namespace std;
int a[1005],b[1005],ans[1005];
int lena=0,lenb=0,Len=0;
void mult(string s1,string s2){
    for(int i=s1.length()-1 ;i>=0;i--){//将数逆转 
    	a[lena]=s1[i]-'0';
    	lena++;
	}
    for(int i=s2.length()-1 ;i>=0;i--){
    	b[lenb]=s2[i]-'0';
    	lenb++;
	}
	if(lena>lenb){
        Len=lena;
	}
	else{
		Len=lenb;
	}
	for(int i=0;i=0;i--){
		if(ans[i]!=0||!flag){  
			flag=false;
			cout<>t;
	getchar();
	for(int i=1;i<=t;i++){
		string s1,s2;
        cin>>s1>>s2;
        getchar();
        cout<<"Case "<