leetcode_4

There are two sorted arrays nums1 and nums2 of size m and n respectively.

Find the median of the two sorted arrays. The overall run time complexity should be O(log (m+n)).

Example 1:

nums1 = [1, 3]
nums2 = [2]

The median is 2.0

Example 2:

nums1 = [1, 2]
nums2 = [3, 4]

The median is (2 + 3)/2 = 2.5

一看到这个题目，就想到了合并归序，就是两部分相加的部分，找到中间两位数即可返回

class Solution {
	public:
		double findMedianSortedArrays(vector& nums1, vector& nums2) {
			int i = 0,j=0,k=0;
			int m = nums1.size();
			int n = nums2.size();
			int num[n+m];
			while(i < m && j < n) {
				if(nums1[i]<=nums2[j]) 
					num[k++]=nums1[i++];
				else 
					num[k++]=nums2[j++];
				if(k==(n+m)/2+1)
					return (double(num[(m+n)/2]+num[(m+n-1)/2])/2.0);
			}
			while (i < m) {
				num[k++]=nums1[i++];
				if(k==(n+m)/2+1)
					return (double(num[(m+n)/2]+num[(m+n-1)/2])/2.0);
			}
			while (j < n) {
				num[k++]=nums2[j++];
				if(k==(n+m)/2+1)
					return (double(num[(m+n)/2]+num[(m+n-1)/2])/2.0);
			}
		}
};