terminate called after throwing an instance of 'std::out_of_range' what(): basic_string::substr

运行时报错:

terminate called after throwing an instance of 'std::out_of_range'
what():  basic_string::substr
Aborted (core dumped)

内存读取越界。

解释1:for example:
const std::string sTest( "test" );
sTest.substr( 0, 10 );
will raise the same exception, since you ask 10 characters, but only 5 ( sTest.length()) ) are available.

调试过,正常运行,无报错。

解释2:

Chances are you did something like:

std::string s("foo");

s.substr(5,1); //the length of the string is 3, 5 is out of bounds

调试过,确实会报错,out_of_range


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