将嵌套List的Map转换为Json应该都没什么问题，使用Gson和Jackson都能实现，在Gson中使用new Gson().toJson()方法，在Jackson中使用new ObjectMapper().writeValueAsString()即可。
将json转换为形如MapMap但是，Map的value的值却并不是List,而是Integer类型的，这里面显然是有问题的，查看Jackson的源码和Gson的源码发现
将json反序列化为对象确实有两个方法，一种适用于泛型对象，一种适用于非泛型的一般对象。
使用Gson
在gson中将json字符串转反序列化为对象有两个方法：
/**
* This method deserializes the specified Json into an object of the specified class. It is not
* suitable to use if the specified class is a generic type since it will not have the generic
* type information because of the Type Erasure feature of Java. Therefore, this method should not
* be used if the desired type is a generic type. Note that this method works fine if the any of
* the fields of the specified object are generics, just the object itself should not be a
* generic type. For the cases when the object is of generic type, invoke
* {@link #fromJson(String, Type)}. If you have the Json in a {@link Reader} instead of
* a String, use {@link #fromJson(Reader, Class)} instead.
*
* @param the type of the desired object
* @param json the string from which the object is to be deserialized
* @param classOfT the class of T
* @return an object of type T from the string. Returns {@code null} if {@code json} is {@code null}.
* @throws JsonSyntaxException if json is not a valid representation for an object of type
* classOfT
*/
public T fromJson(String json, Class classOfT) throws JsonSyntaxException {
Object object = fromJson(json, (Type) classOfT);
return Primitives.wrap(classOfT).cast(object);
}
/**
* This method deserializes the specified Json into an object of the specified type. This method
* is useful if the specified object is a generic type. For non-generic objects, use
* {@link #fromJson(String, Class)} instead. If you have the Json in a {@link Reader} instead of
* a String, use {@link #fromJson(Reader, Type)} instead.
*
* @param the type of the desired object
* @param json the string from which the object is to be deserialized
* @param typeOfT The specific genericized type of src. You can obtain this type by using the
* {@link com.google.gson.reflect.TypeToken} class. For example, to get the type for
* {@code Collection}, you should use:
*
* Type typeOfT = new TypeToken>(){}.getType();
*
* @return an object of type T from the string. Returns {@code null} if {@code json} is {@code null}.
* @throws JsonParseException if json is not a valid representation for an object of type typeOfT
* @throws JsonSyntaxException if json is not a valid representation for an object of type
*/
@SuppressWarnings("unchecked")
public T fromJson(String json, Type typeOfT) throws JsonSyntaxException {
if (json == null) {
return null;
}
StringReader reader = new StringReader(json);
T target = (T) fromJson(reader, typeOfT);
return target;
}
观察fromJson(String json, Class的注释：
It is not suitable to use if the specified class is a generic type since it will not have the generic type information because of the Type Erasure feature of Java
也就是说，由于Java泛型的擦除机制，这个方法不适用于传入泛型的类，比如Map,List等，这个时候可以用T fromJson(String json, Type typeOfT)替代。
下面还有一段话：
Note that this method works fine if the any of the fields of the specified object are generics, just the object itself should not be a generic type
** 注意：** 如果对象不是泛型的，只是字段是泛型的话这个方法是可以使用的
刚开始不太理解这句话，后来想通了，也就是类定义上不能带有泛型比如 public interface Map 这样的就不行，但是如果是下面这样的只有域上带有的泛型是可以：
static class JsonDemo{
private List list;
public List getList() {
return list;
}
public void setList(List list) {
this.list = list;
}
}
下面的fromJson(String json, Type typeOfT)就是专门提供给泛型类的对象使用的，如果你自己反序列化的对象带有泛型的话需要用这个方法。
使用Jackson
和gson一样，jackson也提供了两个方法，一个适用于普通的类，一个适用于泛型类，只不过jackson源码的注释没有Gson的丰富，从注释上看不出来，功能和Gson的一致。
/**
* Method to deserialize JSON content from given JSON content String.
*
* @throws IOException if a low-level I/O problem (unexpected end-of-input,
* network error) occurs (passed through as-is without additional wrapping -- note
* that this is one case where {@link DeserializationFeature#WRAP_EXCEPTIONS}
* does NOT result in wrapping of exception even if enabled)
* @throws JsonParseException if underlying input contains invalid content
* of type {@link JsonParser} supports (JSON for default case)
* @throws JsonMappingException if the input JSON structure does not match structure
* expected for result type (or has other mismatch issues)
*/
@SuppressWarnings("unchecked")
public T readValue(String content, Class valueType)
throws IOException, JsonParseException, JsonMappingException
{
return (T) _readMapAndClose(_jsonFactory.createParser(content), _typeFactory.constructType(valueType));
}
/**
* Method to deserialize JSON content from given JSON content String.
*
* @throws IOException if a low-level I/O problem (unexpected end-of-input,
* network error) occurs (passed through as-is without additional wrapping -- note
* that this is one case where {@link DeserializationFeature#WRAP_EXCEPTIONS}
* does NOT result in wrapping of exception even if enabled)
* @throws JsonParseException if underlying input contains invalid content
* of type {@link JsonParser} supports (JSON for default case)
* @throws JsonMappingException if the input JSON structure does not match structure
* expected for result type (or has other mismatch issues)
*/
@SuppressWarnings({ "unchecked", "rawtypes" })
public T readValue(String content, TypeReference valueTypeRef)
throws IOException, JsonParseException, JsonMappingException
{
return (T) _readMapAndClose(_jsonFactory.createParser(content), _typeFactory.constructType(valueTypeRef));
}
简单实验
使用两种方式反序列一个json，使用Class来反序列化泛型类型的对象，在printType的时候会出现ClassCastException类型转换异常。
package org.xuan;
import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.google.common.collect.Maps;
import com.google.common.reflect.TypeToken;
import com.google.gson.Gson;
import java.io.IOException;
import java.util.Arrays;
import java.util.List;
import java.util.Map;
/**
* Created by zhaohongxuan
*/
public class JsonTest {
private static ObjectMapper mapper = new ObjectMapper();
private static Gson gson = new Gson();
public static void main(String[] args) throws IOException {
Map> map = Maps.newHashMap();
map.put("one", Arrays.asList(10001L, 10002L, 10003L, 10004L));
map.put("two", Arrays.asList(20001L, 20002L, 20003L, 20004L));
map.put("three", Arrays.asList(30001L, 30002L, 30003L, 30004L));
map.put("four", Arrays.asList(40001L, 40002L, 40003L, 40004L));
String json = new Gson().toJson(map);
System.err.println("=======================错误示范=====================");
//Gson
Map> mapResult = gson.fromJson(json,Map.class);
System.out.println("通过Gson转换...");
// printType(mapResult);
System.out.println(mapResult);
//Json
Map> jsonMapResult = mapper.readValue(json,Map.class);
System.out.println("通过Jackson转换...");
// printType(jsonMapResult);
System.out.println(jsonMapResult);
System.out.println("=======================正确做法=====================");
//Gson
Map> mapResult1 = gson.fromJson(json,new TypeToken>>(){}.getType());
System.out.println("通过Gson转换...");
printType(mapResult1);
System.out.println(mapResult1);
//Json
ObjectMapper mapper = new ObjectMapper();
Map> jsonMapResult1 = mapper.readValue(json,new TypeReference< Map>>() {});
System.out.println("通过Jackson转换...");
printType(jsonMapResult1);
System.out.println(jsonMapResult1);
}
public static void printType(Map> map){
for (Map.Entry> entry: map.entrySet()){
System.out.println("key 类型:"+entry.getKey().getClass()+", value类型:"
+entry.getValue().getClass()+", List中元素类型"+entry.getValue().get(0).getClass());
}
}
}
总 结
在Gson中：
如果使用fromJson(String json, Class来反序列化Map的话，不会造成编译错误，返回的类型就会变化，Long类型变成了Double类型,使用的时候就会出现异常，例如在遍历Map的entrySet的时候就会出现异常。
java.lang.ClassCastException: java.lang.Double cannot be cast to java.lang.Long
因此：
- 反序列化
泛型对象如MapfromJson(String json, Type typeOfT) - 一般对象使用
fromJson(String json, ClassclassOfT)
在Jackson中：
如果使用T readValue(String content, Class来反序列化Map的话，返回的类型就会由Long类型变成了Integer类型。valueType) - 反序列化
泛型对象如MapT readValue(String content, TypeReference valueTypeRef) - 一般对象使用
T readValue(String content, ClassvalueType)