poj 1797

和poj2253差不多，都是要边权最大值最小

#include
#include
#include
#include
#include
#include
using namespace std;
#define f first
#define s second
typedef long long LL;
typedef pair PII;
typedef pair PLL;
const int N = 1e3 + 10 ;
const int M = 1e6 + 10 ;
int inq[N],d[N];
int h[N],to[M*2],nt[M*2],cnt,cost[M*2];
int n,m,a,b,c,t,cas;
void add(int u,int v,int c){
	to[++cnt] = v;
	cost[cnt] = c;
	nt[cnt] = h[u];
	h[u] = cnt;
}
void spfa(){
	memset(d,0,sizeof(d));
	memset(inq,0,sizeof(inq));
	d[1] = 1e9;
	queue q;
	q.push(1);
	while(!q.empty()){
		int u = q.front();
		q.pop();
		inq[u] = 0 ;
		for(int i = h[u] ; i ; i = nt[i]){
			int t = to[i];
			int di = cost[i];
			if(d[t] < min(di,d[u])){
				d[t] = min(di,d[u]);
				if(!inq[t]){
					inq[t] = 1;
					q.push(t);
				}
			}
		}
	}
}
int main(){
	//ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
	//freopen("data.in","r",stdin);
	//freopen("data.out","w",stdout);
	scanf("%d",&t);
	while(t--){
		scanf("%d%d",&n,&m);
		cnt = 0 ;
		memset(h,0,sizeof(h));
		for(int i = 0 ; i < m;i ++){
			scanf("%d%d%d",&a,&b,&c);
			add(a,b,c);
			add(b,a,c);
		}
		spfa();
		printf("Scenario #%d:\n%d\n\n",++cas,d[n]);
	}
	return 0;
}