Ｃ语言对数据进行扩大

相信经常做数据分析的常常需要对数据进行放大：比如说现在只有100个数据，现在需要10000个数据才能更好的分析问题，这时候就需要用到数据放大．
需求：下面是900多个数据，把他放大到10000个．
vim 打开如下图：

一部分代码：

40.095,28,29,2545,10790,1
40.833,29,34,2843,11940,1
40.003,31,31,2948,11651,1
40.173,27,27,2851,11751,1
40.029,27,26,2657,10655,1
39.997,28,28,2849,11004,1
40.324,30,28,2876,11689,1
40.584,29,28,2756,11797,1
40.161,29,27,2924,11045,1
41.554,30,30,2929,11114,1
40.977,31,31,2672,10642,1
40.601,33,28,2829,10840,1
41.398,29,27,2623,10718,1
40.725,30,26,2849,11373,1
41.435,28,30,2933,11890,1
41.034,27,30,2920,11496,1
40.677,29,29,2964,10811,1
40.981,27,29,2833,10657,1
39.994,27,27,2684,10946,1
40.489,29,27,2695,10689,1
39.924,31,30,2992,10861,1

解决思路是：先算出各个成员的平均值，最大值，最小值．
然后用最小值，最小值或者平均值加上一个可调节的随机值，让它与原数据拟合程度更高．

下面是求得各个数据（如图）：

代码：

#include 
#include 
#include 

typedef struct dataitem{
        float time_during;
        int first_int;
        int second_int;
        int third_int;
        int fourth_int;
        int flag;
}DATA;
DATA function(char*);
int main()
{
        FILE* fp = NULL;
        char* name = "bot200.csv";
        fp = fopen(name,"rb+");
        if(!fp)
        {
                printf("error!");
                exit(-1);
        }
        DATA item;
        char string[32];
        double time_during = 0.0;
        float first_int =  0;
        float second_int = 0;
        float third_int = 0;
        float fourth_int = 0;
        float flag = 0;
        int i = 0;
        for(i = 0;i < 901;i++)
        {
                fgets(string,sizeof string,fp);
                item = function(string);
                time_during += item.time_during;
                first_int += item.first_int;
                second_int += item.second_int;
                               flag += item.flag;
        }

        printf("time = %lf,first_int = %f,second_int = %f,third_int = %f,fourth_int = %f,flag = %f\n",time_during/i,first_int/i,second_int/i,third_int/i,fourth_int/i,flag/i);

        fclose(fp);

        return 0;
}
DATA function(char* string)
{
        DATA Temp;
        char str[10];
        char* p = strtok(string,",");
        strcpy(str,p);

        int strint = 0,sum = 0;
        for(int i = 0;i < 6;i++)
        {
                if(str[i] == '.')
                        continue;
                strint = str[i]-48;
                sum=sum*10+strint;
        }
        float time_during = sum/1000.000;
        //printf("%f",time_during);

        p = strtok(NULL,",");
        int first_int = atoi(p);

                //printf("%d\t",third_int);

        p = strtok(NULL,",");
        int fourth_int = atoi(p);
        //printf("%d\t",fourth_int);

        p = strtok(NULL,",");
        int flag = atoi(p);
        //printf("%d\n",flag);

        Temp.time_during =  time_during;
        Temp.first_int = first_int;
        Temp.second_int = second_int;
        Temp.third_int= third_int;
        Temp.fourth_int = fourth_int;
        Temp.flag = flag;
        return Temp;
}                                                                                                                     

算出几个关键值，然后根据关键值生成需要的数据
代码如下：

#include 
#include 
#include 

int main()
{
        FILE* fp = NULL;
        char* name = "bot200-1.csv";
        fp = fopen(name,"a+");
        if(!fp)
        {
                printf("error!");
                exit(-1);
        }
        srand(time(NULL));
        float time_during;
        int first_int;
        int second_int;
        int third_int;
        int fourth_int;
        int flag;
        char string[26];
        for(int i = 0;i < 10000;i++)  
        {
                time_during = (rand()%7000)/1000.000+34.678;
                first_int = rand()%13+26;
                second_int = rand()%14+26;
                third_int = rand()%1774+1995;
                fourth_int = rand()%1980+11177;
                flag = rand()%2+1;
                sprintf(string,"%2.3f,%2d,%2d,%4d,%5d,%1d\n",time_during,first_int,second_int,third_int,fourth_int,flag);
//              printf("%s",string);

                fwrite(string,sizeof(string),1,fp);
        }

        fclose(fp);
        return 0;
}

生成的数据：

当然你也可以把这两个文件合成一个文件．
其他的数据放大与这思路类似．