找出所有从根节点到叶子节点路径和等于n的路径并输出

package create;

import java.util.Deque;
import java.util.Enumeration;
import java.util.LinkedList;
import java.util.Queue;
import java.util.Stack;
/**
 * 创建二叉排序树，二叉树的六种遍历
 * @author root
 *
 */
public class BiTreeTest {

	static class Node{
		int value;
		Node left = null;
		Node right = null;
		public Node(int value){
			this.value = value;
		}
	}
	public static void main(String[] args) {
		// TODO Auto-generated method stub
		//int []data = {6,5,3,4,2,8,7,9,1};
		int []data = {8,9,5,3,6,2,4,7};
		BiTreeTest bt = new BiTreeTest();
		
		Node root = bt.creatBiTree(data);
		//System.out.println(bt.getDepth(root));
		bt.findPath(root , 15);
	}
	
	//创建二叉排序树
	public Node creatBiTree(int []data){
		Node root = new Node(data[0]);
		for(int i=1; i stack = new Stack();
	/**
	 * 找出所有从根节点到叶子节点路径和等于n的路径并输出
	 * @param root
	 * @param n
	 */
	public void findPath(Node root ,int n){
		if(root!=null){
			stack.push(root);
			n = n-root.value;
			if(n==0 && root.left==null && root.right==null){//是所求的叶子节点
				for(Node no:stack){
					System.out.print(no.value);
				}
				System.out.println();
			}
			
			findPath(root.left, n);
			findPath(root.right, n);
			stack.pop();
		}
	}
}