SQL 中将14位数字快速转换为时间

示例

 
declare @str varchar(14)
set @str='20080210182031'

select cast(left(@str,8) as datetime)+stuff(stuff(right(@str,6),3,0,':'),6,0,':')

输出结果

2008-02-10 18:20:31.000

转载于:https://www.cnblogs.com/xiaobier/archive/2009/02/19/1393953.html