HOJ-1962

Source : Waterloo ACM Programming Contest Sep 28, 2002
Time limit : 1 sec
Memory limit : 32 M
It is said that 90% of frosh expect to be above average in their class. You are to provide a reality check.

Input

The first line of standard input contains an integer C, the number of test cases. C data sets follow. Each data set begins with an integer, N, the number of people in the class (1 <= N <= 1000). N integers follow, separated by spaces or newlines, each giving the final grade (an integer between 0 and 100) of a student in the class.

Output
For each case you are to output a line giving the percentage of students whose grade is above average, rounded to 3 decimal places.
Sample Input
5
5 50 50 70 80 100
7 100 95 90 80 70 60 50
3 70 90 80
3 70 90 81
9 100 99 98 97 96 95 94 93 91

Sample Output
40.000%
57.143%
33.333%

66.667%

55.556%

#include 
#include 
using namespace std;

int main(int argc, char const *argv[])
{
	int C = 0;
	cin >> C;
	double *above = new double[C];
	for (int i = 0, N = 0; i < C; ++i)
	{
		cin >> N;
		int *Grate = new int[N];
		int total_Grate = 0;
		for (int j = 0; j < N; ++j)
			{
				cin >> Grate[j];
				total_Grate += Grate[j];
			}	 	
		int Aver_Grate = total_Grate / N;
		double k = 0;
		for (int f = 0; f < N; ++f)
			if( Grate[f] > Aver_Grate )
				++k;
		above[i] = 100 * (k / N);	 	
		delete Grate; 
	}
	for (int i = 0; i < C; ++i)
		printf("%.3f%%\n", above[i]);
	return 0;
}