python调用c++接口传递opencv格式图像

关于python调用c++接口的方法，网上有好多例子，不在赘述了。

文件结构如下：

 直接上代码：

opencvcall.cpp

#include 

using namespace cv;

extern "C"
{
    void test(int height, int width, uchar* frame_data)
    {
        int count = 0;

        Mat image(height, width, CV_8UC3);
        uchar* pxvec =image.ptr(0);
        
        for(int row = 0; row < height; row++)
        {
            pxvec = image.ptr(row);
            for(int col = 0; col < width; col++)
            {
                for(int c = 0; c < 3; c++)
                {
                    pxvec[col*3+c] = frame_data[count];
                    count++;
                }
            }
        }

        imshow("result", image);
        waitKey(0);
        return;
    }
}

 makefile

libopencvcall.so:
	g++ -o libopencvcall.so -shared -fPIC opencvcall.cpp -lopencv_core -lopencv_highgui -lopencv_imgcodecs

 pycall.py

import cv2   
import ctypes
import numpy as np

ll = ctypes.cdll.LoadLibrary
lib = ll("./libopencvcall.so")
lib.test.restype = ctypes.c_float
frame = cv2.imread('1.jpg')
frame_data = np.asarray(frame, dtype=np.uint8)
frame_data = frame_data.ctypes.data_as(ctypes.c_char_p)
lib.test(frame.shape[0], frame.shape[1], frame_data)

 首先执行make，当前目录下会生成libopencvcall.so动态库文件，然后执行pycall.py，读取当前目录下的1.jpg图片，通过libopencvcall.so生成的接口调用opencvcall.cpp中的test接口，显示图片：