Given a positive integer n, generate a square matrix filled with elements from 1 to n2 in spiral order.
给一个正整数 n 生成一个 矩阵 覆盖 从 1 到 n^2 的 螺旋矩阵
Input: 3
Output:
[
[ 1, 2, 3 ],
[ 8, 9, 4 ],
[ 7, 6, 5 ]
]
承接上题螺旋矩阵
class Solution {
public int[][] generateMatrix(int n) {
int [][] ans = new int [n][n];
int r =0, c = 0,di = 0;;
int[] dr = {0, 1, 0, -1};
int[] dc = {1, 0, -1, 0};
int r0 = 0, r1 = n,c0 = 0,c1 = n;
int cr ,cc;
for(int i = 1 ; i <= n*n; i++){
ans[r][c] = i;
cr = r + dr[di];
cc = c + dc[di];
if (r0 <= cr && cr < r1 && c0 <= cc && cc < c1 ){
r = cr; // r下一个位置
c = cc; // c 下一个位置
}else{
di = (di + 1) % 4;
r += dr[di];
c += dc[di];
if(dr[di] ==1 ){
r0++;
}
if(dr[di] == -1){
r1--;
}
if(dc[di] == 1){
c0++;
}
if(dc[di] == -1){
c1--;
}
}
}
return ans;
}
}