golang 字符串相似度算法

在使用cobra的时候，如果输入的command不对，会提示：

$ go run main.go pring katy
Error: unknown command "pring" for "cobra"

Did you mean this?
        print

很好奇这个怎么做的，没想到这竟然是一个字符串相似度的算法题 。

 

题目： 一个字符串可以通过增加一个字符，删除一个字符，替换一个字符得到另外一个字符串，假设，我们把从字符串A转换成字符串B，前面3种操作所执行的最少次数称为AB相似度
如  abc adc  度为 1
      ababababa babababab 度为 2
      abcd acdb 度为2


 字符串相似度算法可以使用 Levenshtein Distance算法(中文翻译：编辑距离算法) 这算法是由俄国科学家Levenshtein提出的。其步骤

Step	Description
1	Set n to be the length of s. Set m to be the length of t. If n = 0, return m and exit. If m = 0, return n and exit. Construct a matrix containing 0..m rows and 0..n columns.
2	Initialize the first row to 0..n. Initialize the first column to 0..m.
3	Examine each character of s (i from 1 to n).
4	Examine each character of t (j from 1 to m).
5	If s[i] equals t[j], the cost is 0. If s[i] doesn't equal t[j], the cost is 1.
6	Set cell d[i,j] of the matrix equal to the minimum of: a. The cell immediately above plus 1: d[i-1,j] + 1. b. The cell immediately to the left plus 1: d[i,j-1] + 1. c. The cell diagonally above and to the left plus the cost: d[i-1,j-1] + cost.
7	After the iteration steps (3, 4, 5, 6) are complete, the distance is found in cell d[n,m].

 代码位置：https://github.com/spf13/cobra/cobra.go#ld

// ld compares two strings and returns the levenshtein distance between them.
func ld(s, t string, ignoreCase bool) int {
	if ignoreCase {
		s = strings.ToLower(s)
		t = strings.ToLower(t)
	}
	d := make([][]int, len(s)+1)
	for i := range d {
		d[i] = make([]int, len(t)+1)
	}
	for i := range d {
		d[i][0] = i
	}
	for j := range d[0] {
		d[0][j] = j
	}
	for j := 1; j <= len(t); j++ {
		for i := 1; i <= len(s); i++ {
			if s[i-1] == t[j-1] {
				d[i][j] = d[i-1][j-1]
			} else {
				min := d[i-1][j]
				if d[i][j-1] < min {
					min = d[i][j-1]
				}
				if d[i-1][j-1] < min {
					min = d[i-1][j-1]
				}
				d[i][j] = min + 1
			}
		}

	}
	return d[len(s)][len(t)]
}