【CCF历年题题解】202006-4 1246【动态规划】

暴力法（26分）

参考地址

#include 
#include 
#include 

using namespace std;

const int N = 1010 ,mod = 998244353;

int n;
string S;
string s[N];

int main()
{
     
    cin >> n >> S;
    s[1] = "2",s[2] = "4",s[3] = "16", s[4] = "264", s[5] = "46416";
    
    for(int i=5; i <= n ; i ++)
    {
     
        s[i] = s[i-3] + s[i-1].substr(s[i-4].size()) + s[i-2];
    }
    
    int p = s[n].find(S);
    int cnt = 0;
    while(p != -1)
    {
     
        cnt = (cnt + 1) % mod;
        p++;
        p = s[n].find(S,p);
        
    }
    
    cout<<cnt<<endl;
    
    return 0;
    
}

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