mysql中查询一段时间的日期,要把没数据的日期也展示出来的方法如下:
mysql获取两个日期内的所有日期列表:
select t1.create_time ,ifnull(t2.yuyin_order_nums,0)yuyin_order_nums,IFNULL(t2.yuyin_ordersuccess_nums,0) yuyin_ordersuccess_nums,
ifnull(t2.yuyin_percent,'0.00%')yuyin_percent,ifnull(t2.yuyin_deal_nums,0)yuyin_deal_nums,
ifnull(t3.shaoma_order_nums,0)shaoma_order_nums,IFNULL(t3.shaoma_ordersuccess_nums,0) shaoma_ordersuccess_nums,
ifnull(t3.shaoma_percent,'0.00%')shaoma_percent,ifnull(t3.shaoma_deal_nums,0)shaoma_deal_nums
from
(select @num:=@num+1,date_format(adddate('2017-10-01', INTERVAL @num DAY)-1,'%Y-%m-%d') as create_time
from np_order,(select @num:=0) t where adddate('2017-10-01', INTERVAL @num DAY) <= date_format('2017-11-01','%Y-%m-%d')
order by create_time ) t1
LEFT JOIN
(
select DATE_FORMAT(m.create_time,'%Y-%m-%d') create_time ,count(1) yuyin_order_nums ,
sum(
CASE when m.order_status ='2' then
1
ELSE
0
end ) yuyin_ordersuccess_nums,
concat(FORMAT((
sum(
CASE when m.order_status ='2' then
1
ELSE
0
end )/count(1))*100,2),'%') yuyin_percent,
sum(
CASE when m.order_status ='4' then
1
ELSE
0
end ) yuyin_deal_nums
from np_order m where m.order_m_type in ('19')
and m.create_time >='2017-08-01'
and m.create_time <'2017-11-01'
group by DATE_FORMAT(m.create_time,'%Y-%m-%d') ) t2
on t1.create_time =t2.create_time
LEFT JOIN
(
select DATE_FORMAT(m.create_time,'%Y-%m-%d') create_time ,count(1) shaoma_order_nums ,
sum(
CASE when m.order_status ='2' then
1
ELSE
0
end ) shaoma_ordersuccess_nums,
concat(FORMAT((
sum(
CASE when m.order_status ='2' then
1
ELSE
0
end )/count(1))*100,2),'%') shaoma_percent,
sum(
CASE when m.order_status ='4' then
1
ELSE
0
end ) shaoma_deal_nums
from np_order m where m.order_m_type in ('20')
and m.create_time >='2017-08-01'
and m.create_time <'2017-11-01'
group by DATE_FORMAT(m.create_time,'%Y-%m-%d') ) t3
on t1.create_time =t3.create_time
order by t1.create_time ;
此方法优点就是不需要创建存储过程或者是日历表,缺点就是你必须要有一个表,它的数据条数大到足够支撑你要查询的天数
,也就是说比如
np_order 表 总条数是 20条的话,那你查询的时间是一个月,那就需要30条数据,那最多会只给你展示20条,所以要保证 np_order 表要超过你查询的天数
来自 “ ITPUB博客 ” ,链接:http://blog.itpub.net/31369373/viewspace-2146893/,如需转载,请注明出处,否则将追究法律责任。