假设nn的稀疏矩阵A采用三元组表示,设计一个程序exp6-4.cpp实现如下功能:
(1)生成如下两个稀疏矩阵的三元组a和b;
(2)输出a转置矩阵的三元组;
(3)输出a+b的三元组;
(4)输出ab的三元组。
#include
#include
#define MaxSize 16
#define M 4
#define N 4
typedef struct
{
int r;
int c;
int d;
} TupNode;
typedef struct
{
int rows;
int cols;
int nums;
TupNode data[MaxSize];
} TSMatrix;
void CreatMat(TSMatrix *t,int A[][N])
{
int i,j;
t->cols=N;
t->rows=M;
t->nums=0;
for(i=0; idata[t->nums].c=j;
t->data[t->nums].r=i;
t->data[t->nums].d=*(A[i]+j);
t->nums++;
}
}
}
void OutputMat(TSMatrix *t)
{
int i;
printf(" %d %d %d\n",M,N,t->nums);
printf(" -----------\n");
for(i=0; inums; i++)
{
printf(" %d %d %d\n",t->data[i].r,t->data[i].c,t->data[i].d);
}
}
void TranTat(TSMatrix *t,TSMatrix *a)
{
t->cols=a->rows;
t->rows=a->cols;
t->nums=a->nums;
int i,j,k=0;
for(i=0; icols; i++)
for(j=0; jnums; j++)
if(i==a->data[j].c)
{
t->data[k].c=a->data[j].r;
t->data[k].r=a->data[j].c;
t->data[k].d=a->data[j].d;
k++;
}
}
void SumMat(int a[][N],int b[][N],int c[][N])
{
int i,j;
for (i = 0; i < M; i++)
for (j = 0; j < N; j++)
c[i][j] = a[i][j] + b[i][j];
}
void MultiMat(int a[][N],int b[][N],int c[][N])
{
int i,j,k,sum;
for (i = 0; i < M; i++)
{
for (j = 0; j < N; j++)
{
sum = 0;
for (k = 0; k < N; k++)
{
sum += a[i][k] * b[k][j];
}
c[i][j]=sum;
}
}
}
int main()
{
int A[M][N]= {{1,0,3,0},{0,1,0,0},{0,0,1,0},{0,0,1,1}},B[][N]= {{3,0,0,0},{0,4,0,0},{0,0,1,0},{0,0,0,2}},C[M][N];
TSMatrix *a,*b,*c;
a=(TSMatrix *)malloc(sizeof(TSMatrix));
b=(TSMatrix *)malloc(sizeof(TSMatrix));
c=(TSMatrix *)malloc(sizeof(TSMatrix));
printf("a的三元组:\n");
CreatMat(a,A);
OutputMat(a);
printf("b的三元组:\n");
CreatMat(b,B);
OutputMat(b);
printf("a转置为c\n");
printf("c的三元组:\n");
TranTat(c,a);
OutputMat(c);
printf("c=a+b\n");
printf("c的三元组:\n");
SumMat(A,B,C);
CreatMat(c,C);
OutputMat(c);
printf("c=a*b\n");
printf("c的三元组:\n");
MultiMat(A,B,C);
CreatMat(c,C);
OutputMat(c);
return 0;
}