杭电ACM1001Sum Problem(1~n的和)

Sum Problem

Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 334319    Accepted Submission(s): 84056

Problem Description

Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.

 

Input

The input will consist of a series of integers n, one integer per line.

 

Output

For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.

 

Sample Input

1 100

 

Sample Output

1 5050

注：此题为： 杭电ACM1001Sum Problem(1~n的和)

说明：累加，注意输出格式

已AC源代码：

#include
int main()
{
	int n;
	while(scanf("%d",&n)!=EOF)
	{
		int i,sum=0;
		for(i=1;i<=n;i++)
		{
			sum+=i;
		}
		printf("%d\n",sum);
	}
	return 0;
}