HDUOJ1021 Fibonacci Again

Fibonacci Again

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 21187    Accepted Submission(s): 10145

Problem Description

There are another kind of Fibonacci numbers: F(0) = 7, F(1) = 11, F(n) = F(n-1) + F(n-2) (n>=2).

 

 

Input

Input consists of a sequence of lines, each containing an integer n. (n < 1,000,000).

 

 

Output

Print the word "yes" if 3 divide evenly into F(n).

Print the word "no" if not.

 

 

Sample Input

0 1 2 3 4 5

 

 

Sample Output

no no yes no no no

 

#include 
#define maxn 1000010
int str[maxn];
int main()
{
       int i,x;
    str[0]=1;str[1]=2;
    for(i=2;i)
        str[i]=(str[i-1]+str[i-2])%3;
    while(scanf("%d",&x)!=EOF)
    {
        
    printf("%s\n",str[x]%3==0?"yes":"no");
    }
    return 0;

 

转载于:https://www.cnblogs.com/zhaojiedi/archive/2012/07/27/2613426.html