微信小程序两个数组的去重操作

1、tran.js 存在两个不同但却有相同属性值的数组（arr1,arr2）：

data: {

    arr1:[
      {
        "id":1,
        "name":"html",
        "read":108987
      },
      {
        "id":2,
        "name":"css",
        "read":5489564
      },
      {
        "id":3,
        "name":"javascript",
        "read":523698
      },
      {
        "id":4,
        "name":"php",
        "read":6985649
      }
    ],
    arr2:[
      {
        "id":1,
        "name":"html",
        "read":108987
      },
      {
        "id":2,
        "name":"css",
        "read":5489564
      },
      {
        "id":3,
        "name":"javascript",
        "read":523698
      },
      {
        "id":4,
        "name":"php",
        "read":6985649
      },
      {
        "id":5,
        "name":"thinkphp",
        "read":9898774
      },
      {
        "id":6,
        "name":"python",
        "read":6888768
      },
      {
        "id":7,
        "name":"wx",
        "read":50123698
      },
      {
        "id":8,
        "name":"game",
        "read":58496491
      }
      ,{
        "id":9,
        "name":"youxiu",
        "read":58496491
      },
      {
        "id":10,
        "name":"niubi",
        "read":58496491
      }
    ]
  },

2、定义一个函数getData进行去重操作：

// 去重操作
  getdata(){
    const a1 = this.data.arr1
    const a2 = this.data.arr2

    for(let i=0,len=a2.length;i

** 第一个for循环是 循环来源数据，第二for循环是循环已有数据，然后通过比较返回全部数据 **

== flag 用于判断是否重复，循环已有数据时，如果存在唯一属性相等（本题是id）则flag 为false，也就是排除。 ==

** 最后在进行组装连接形成新的arr1数组 **

3、结果如下：