算法学习：leetcode 1 two-sum 两数之和之go语言实现

0x00 题干

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

来源：力扣（LeetCode） 链接：https://leetcode-cn.com/problems/two-sum
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0x01 分析

**题目大意：**给出一个数组以及目标值，在这个数组中找相关的两个数，确保两个数的和与目标值相等，返回这两个数的下表

**思路：**很简单，两层遍历，找到对应的值即可。当然可以使用map进行优化。

0x02 题解

func twoSum(nums []int, target int) []int {
     
	for i := 0; i < len(nums); i++ {
     
		for j := i + 1; j < len(nums); j++ {
     
			if nums[i] + nums[j] == target {
     
				return [] int{
     i, j}
			}
		}
	}
	return nil
}

代码实现见：https://github.com/totalo/leetcode-go/blob/master/two-sum.go